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tatuchka [14]
3 years ago
9

I need step by step please

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

86.67 %

Step-by-step explanation:

8 were penalties, so 60-8=52 were not penalties.

so 52 out of 60 were not penalties.

52/60 * 100% = 86.67 %

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Maya goes bowling with her friends. She has a total of $25 to spend. If shoes cost $4 to
IRINA_888 [86]

Answer:

She can play 7 games

Step-by-step explanation:

Substrate 4 from 25

7 0
3 years ago
How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?
MrRissso [65]
\left( \frac{27x^3}{8y^9}\right)^ \frac{5}{3}  \\\\\\ =\left( \frac{(3x)^3}{(2y^3)^3}\right)^ \frac{5}{3} \\\\\\ =  \frac{(3x)^{3 \times  \frac{5}{3} }}{(2y^3)^{3 \times  \frac{5}{3} }} \\\\\\ =\frac{(3x)^5}{(2y^3)^{5 }} \\\\\\ =\frac{243x^5}{32y^{15}}

Now, If the exponent was negative like you asked....

\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}

5 0
3 years ago
Please help ASAP 40 PTS
umka21 [38]

Answer:

70

Step-by-step explanation:

The angle not marked in the top triangle is 40 degrees since it is an isosceles triangle.  That makes the angle opposite it in the other triangle 40 degrees since they are vertical angles and vertical angles are equal.

The bottom triangle has 3 angles that sum to 180 degrees,  The other angle not marked is also y since it is an isosceles triangle.

40 + y +y = 180

Subtract 40 from each side and combine like terms

40-40 +2y = 180-40

2y = 140

Divide by 2

2y/2 = 140/2

y = 70

3 0
3 years ago
Read 2 more answers
Please answer this quick
Darya [45]

(3x + 20degrees )  = 180degrees

180 degress because a stranight angle equals that

3 0
3 years ago
Find a such that the solution of y'' + y' − 2y = 0, y(0) = a, y' (0) = 1 tends to zero as t → +∞.
Kay [80]

Answer:

Step-by-step explanation:

y'' + y' − 2y = 0, y(0) = a, y' (0) = 1

Auxialary equation is

m^2+m-2=0\\m=-2,1

General solution is

y=Ae^{-2x} +Be^x

y(0) = A+B =a

y'(0) = -2Ae^{2x} +Be^x = -2A+B = 1

Eliminate B to get

3A =a-1

We know that y tends to 0 when x tends to infinity for any finite A

i.e. a should be a finite real number.

8 0
3 years ago
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