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Natalka [10]
2 years ago
6

Need Urgent help! Someone please answer it

Mathematics
1 answer:
Fiesta28 [93]2 years ago
7 0

Answer:

yes

no

no

no

.............

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I will give brainliest and offer good points (01.04 MC<br> )Solve 4 ⋅ (−6).
Alchen [17]

Answer:

the answer is -24

Step-by-step explanation:

7 0
4 years ago
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A school bought 32 new desks. Each desk cost $24. Estimate how much the school spent on the new desk?
Arte-miy333 [17]
32 times 24 is $768 which us how much they spent
3 0
3 years ago
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Which of the following is not an identity?
OLga [1]
D. csc^2 x + sec^2 x = 1


The process for each option is to rewrite the equation, attempting to obtain the identity sin^2 x + cos^2 x = 1. In general convert each function to its equivalent using just sin and cos.


A. cos^2 x csc x - csc x = -sin x
cos^2 x * 1/sin x - 1/sin x = -sin x
(cos^2 x * 1/sin x - 1/sin x) * sin x = -sin x * sin x
cos^2 x * 1 - 1 = -sin^2 x
cos^2 x = -sin^2 x + 1
cos^2 x + sin^2 x = 1
Option A is an identity.


B. sin x(cot x + tan x) = sec x
sin x(cos x/sin x + sin x/cos x) = 1/cos x
cos x + sin^2 x/cos x = 1/cos x
cos^2 x + sin^2 x = 1
Option B is an identity.


C. cos^2 x - sin^2 x = 1- 2sin^2 x
cos^2 x - sin^2 x + 2sin^2 x = 1- 2sin^2 x + 2sin^2 x
cos^2 x + sin^2 x = 1
Option C is an identity.


D. csc^2 x + sec^2 x = 1
1/sin^2 x + 1/cos^2 x = 1
cos^2 x/(cos ^2 x sin^2 x) + sin^2 x/(cos^2 x sin^2 x) = 1
(cos^2 x + sin^2 x)/(cos ^2 x sin^2 x) = 1
1/(cos ^2 x sin^2 x) = 1
1 = cos ^2 x sin^2 x
Option D is NOT an identity.


6 0
4 years ago
HELP! I'm bad at math!!
Nikolay [14]

Answer:

6÷1/4= 24

8÷1/3= 24

1/4÷3= 1/12

3÷1/2= 6

6÷3/5= 10

hope this helped :)

Step-by-step explanation:

5 0
4 years ago
What's the first step in finding the value of x??
konstantin123 [22]
Eliminating any brackets that there are.

Hope this helps :)
7 0
3 years ago
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