Answer:
a i belive
Explanation:
the univerce is VERY large so a, if im wrong i apologise :(
Answer:
T= 4.24sec
Explanation:
We are going to use the formula below to calculate.
Where T is period
L is length of rod
g is acceleration due to gravity =
From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this
= 4.4625m
thus
T= 4.24sec
Answer:
The magnitude of the angular momentum of the Mars in a circular orbit around the sun is
Explanation:
Given that,
Mass of mars
Radius
Orbit radius
Time period = 687 days
We need to calculate the magnitude of the angular momentum of the mars
Using formula of angular momentum
Here,
Where,
L = angular momentum
I = moment of inertia
r = radius
=angular speed
Put the value into the formula
Hence, The magnitude of the angular momentum of the Mars in a circular orbit around the sun is
Answer:
-4.8 m/s²
Explanation:
Apply Newton's second law:
∑F = ma
F − mg = ma
300 N − (60 kg) (9.8 m/s) = (60 kg) a
a = -4.8 m/s²
The acceleration five seconds after jumping is 4.8 m/s² downward.