what factors are associated with the advanced performance of japanese students on standardized tests?

Howard woke up and turned on his lamp. Also, he turned on the television to hear the weather. He walked to the bathroom to

Hoochie [10]

Answer: 5 words >>>> he is living a life

Explanation:

4 0

3 years ago

Which of these will have the same units if acceleration is multiplied by time? Force Time velocity Pressure

Leno4ka [110]

Answer:

Velocity

Explanation:

Velocity equals the original velocity... Plus

the acceleration is multiplied by time.

8 0

3 years ago

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A car is traveling at 26.0 m/s when the driver suddenly applies the brakes, causing the car to slow down with constant accelerat

UkoKoshka [18]

Answer:

a = -2.82 m/s²

v = 18.4 m/s

Explanation:

Initial velocity, u = 26.0 m/s

Final velocity, v = 0 m/s

Distance travelled, s = 120m

Using

v² = u² + 2as

0 = 26² + 2(120)a

a= -2.82 m/s²

Velocity of the car when it was 60.0m past the point where the brakes were applied:

u = 26.0 m/s

a = -2.82 m/s²

s = 60m

Using

v² = u² + 2as

v² = 26² + 2(-2.82)(60)

v² = 337.6

v = 18.4 m/s

5 0

3 years ago

A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10

sashaice [31]

Answer:

Time interval;Δt ≈ 37 seconds

Explanation:

We are given;

Angular deceleration;α = -1.6 rad/s²

Initial angular velocity;ω_i = 59 rad/s

Final angular velocity;ω_f = 0 rad/s

Now, the formula to calculate the acceleration would be gotten from;

α = Change in angular velocity/time interval

Thus; α = Δω/Δt = (ω_f - ω_i)/Δt

So, α = (ω_f - ω_i)/Δt

Making Δt the subject, we have;

Δt = (ω_f - ω_i)/α

Plugging in the relevant values to obtain;

Δt = (0 - 59)/(-1.6)

Δt = -59/-1.6

Δt = 36.875 seconds ≈ 37 seconds

6 0

4 years ago

A NASA explorer spacecraft with a mass of 1,000 kg takes off in a positive direction from a stationary asteroid. If the velocity

Georgia [21]

Answer: 10000 kg

Explanation:

The momentum $p$ is given by the following equation:

$p=m.V$ (1)

Where:

$m$ is the mass of the object

$V$ is the velocity of the object

Now, in this case and according the conservation of momentum:

$m_{1}v_{1}+m_{2}v_{2}=m_{1}u_{1}+m_{2}u_{2}$ (2)

Where:

$m_{1}=1000kg$ is the mass of the spacecraft

$m_{2}$ is the mass of the asteroid

$v_{1}=0$ is the initial velocity of the spacecraft

$v_{2}=0$ is the initial velocity of the asteroid (because we are told the asteroid is stationary, as the spacracft is on the sateroid it remains stationary as well)

$u_{1}=250m/s$ is the final velocity of the spacecraft

$u_{2}=-25m/s$ is the final velocity of the asteroid

Rewritting (2):

$0=m_{1}u_{1}+m_{2}u_{2}$ (3)

$0=(1000kg)(250m/s)+m_{2}(-25m/s)$ (4)

Finding $m_{2}$ :

$m_{2}=10000kg$ This is the mass of the asteroid

3 0

3 years ago

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