Construct a quadratic equation whoose root are 1 √7-2 and √7+2
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Answer:
log9
Step-by-step explanation:
Using the rules of logarithms
logx + logy = log(xy)
logx - logy = log()
log ⇔ nlogx
Given
2(log18- log3) + log
= 2(log( ) ) + log
= 2log6 + log
= log6² + log
= log36 + log
= log( 36 × )
= log9