This question above is incomplete
Complete Question
Jim had 103 red and blue marbles. After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles. How many blue marbles did he have originally?
Answer:
70 Blue marbles
Step-by-step explanation:
Let red marbles = R
Blue marbles = B
Step 1
Jim had 103 red and blue marbles.
R + B = 103.......Equation 1
R = 103 - B
Step 2
After giving 2/5 of his blue marbles and 15 of his red marbles to Samantha, Jim had 3/7 as many red marbles as blue marbles
2/5 of B to Samantha
Jim has = B - 2/5B = 3/5B left
He also gave 15 red marbles to Samantha
= R - 15
The ratio of what Jim has left
= Red: Blue
= 3:7
= 3/7
Hence,
R - 15/(3/5)B = 3/7
Cross Multiply
7(R - 15) = 3(3/5B)
7R - 105 = 3(3B/5)
7R - 105 = 9B/5
Cross Multiply
5(7R - 105) = 9B
35R - 525 = 9B............ Equation 2
From Equation 1, we substitute 103 - B for R in Equation 2
35(103 - B) - 525 = 9B
3605 - 35B - 525 = 9B
Collect like terms
3605 - 525 = 9B + 35B
3080 = 44B
B = 3080/44
B = 70
Therefore, Jim originally had 70 Blue marbles.
It should be noted that the value of 597 subtracted from 884 is 287.
<h3>How to illustrate the subtraction?</h3>
The information is simply that we should subtract 884 and 597 and also illustrate it.
This will be:
884 - 597 = 287.
A word problem illustrating this is that a man had 884 pens and gave 597 pens to his friends. How many pens does he have left?
This will be:
= 884 - 597 = 287
Learn more about subtraction on:
brainly.com/question/220101
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More = Addition
"Twice a Number" = Multiplication (specifically by two)
Since the order of operations tell us to multiply before we add, we can simplify
.
Answer:
The answer is 5.
Step-by-step explanation:
$147 subtract parking is $135.
Then divide the $135 by the cost of person which is $27.
Answer: 5
Answer:
Students ticket = $4
Child ticket = $1
Adult ticket = $5
Step-by-step explanation:
Let the price of the student ticket be $x and the price of a child ticket be $y. An adult ticket costs as much as the combined cost of a student ticket and a child ticket, so the price of one adult ticket is $(x+y).
1. A movie theater advertises that a family of two adults, one student, and one child between the ages of 3 and 8 can attend a movie for $15. Then
2. If you purchase 1 adult ticket, 4 student tickets, and 2 child tickets for $23, then
Now, solve the system of two equations:
Solve the last equation
Students ticket = $4
Child ticket = $1
Adult ticket = $5
