2 years ago

Construct a quadratic equation whoose root are 1 √7-2 and √7+2

Mathematics

1 answer:

Dimas [21]2 years ago

4 0

Answer:

Brainliest pls

Step-by-step explanation:

−14x+29=0

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2 years ago

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sergiy2304 [10]

Given:

$$x^{2} y^{8} \cdot \frac{x^{3} y^{?}}{x y^{3}}=x^{4} y^{2}$

To find:

The missing value.

Solution:

Let the missing value be m.

$$x^{2} y^{8} \cdot \frac{x^{3} y^{m}}{x y^{3}}=x^{4} y^{2}$

Using exponent rule: $a^m \cdot a^n=a^{m+n}$

$$ \frac{x^{2+3} y^{8+m}}{x y^{3}}=x^{4} y^{2}$

$$ \frac{x^{5} y^{8+m}}{x y^{3}}=x^{4} y^{2}$

Using exponent rule: $\frac{a^m}{a^n} =a^{m-n}$

$$ x^{5-1} y^{8+m-3}=x^{4} y^{2}$

$$ x^{4} y^{5+m}=x^{4} y^{2}$

Equate x terms and y terms.

$x^4=x^4$ and $y^{5+m}=y^2$

If the bases are same, then the powers are equal.

$5+m=2$

Subtract 5 from both sides.

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$m=-3$

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2 years ago

Construct a quadratic equation whoose root are 1 √7-2 and √7+2​

Construct a quadratic equation whoose root are 1 √7-2 and √7+2