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3 years ago

Which system of equations has the same solution as the system below?

Mathematics

1 answer:

pav-90 [236]3 years ago

6 0

Answer: (1) (2) (4)

Step-by-step explanation:

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Solve by elimination x-5y=35 and 3x-6y=51

IrinaVladis [17]

Answer: x=5 y=-6

(5,-6)

Step-by-step explanation:

Solve by elimination

$\begin{bmatrix}x-5y=35\\ 3x-6y=51\end{bmatrix}$

multiply x-5y=35 by 3

= 3x-15y=105

$\begin{bmatrix}3x-15y=105\\ 3x-6y=51\end{bmatrix}$

$3x-6y=51$

- $\underline{3x-15y=105}$

$9y=-54$

divide 9 on both sides

y= -6

Now solve for x

you must plug in -6 for y in either equations

i plugged in -6 for y in 3x-15y=105

$3x-15\left(-6\right)=105$

$3x+15\cdot \:6=105$

$15\cdot \:6=90$

$3x+90=105$

subtract 90 on both sides

$3x=15$

$\frac{3x}{3}=\frac{15}{3}$

$x=5$

Please mark brainliest

3 0

4 years ago

Read 2 more answers

Find the zeros of (x^2+4) (x-3)

Mila [183]

A multiplication is zero if and only if at least one of the factors is zero. So, in this case, the multipications equals zero when

$x^2+4 = 0 \quad \lor \quad x-3=0$

The first equation has no real solutions, because $x^2$ is a square, and thus it's positive. If you add 4 to a positive number, the result can't be zero.

The second equation has the solution

$x-3=0 \iff x=3$

So, globally, the expression equals zero if and only if $x=3$

8 0

4 years ago

Quadrilateral ABCD is translated 2 units left and 3 units up to form quadrilateral A'B'C'D'

TiliK225 [7]

The answer would be
<span>B)
A' (-8, 5)
B' (-8, 8)
C' (-5, 7)
D' (-4.5, 5)</span>

3 0

3 years ago

Wang Yan drove her truck. The fuel remaining in the truck's tank (in liters) as a function of distance (in kilometers) is graphe

vredina [299]

Answer:

Step-by-step explanation:

5/6 liters

8 0

3 years ago

What is the answer to y=3+8.5x,when x =-4.

-Dominant- [34]

Answer:

y= -31

Step-by-step explanation:

8.5(-4)= -34

-34+3= -31

5 0

3 years ago