Answer:
It's divided by the portions of the planet that hold life.
- The Lithosphere: The continental land of the planet.
- The Hydrosphere: The aquatic portion of the planet.
- The Atmosphere: The air living creatures breathe.
Explanation:
Apply antibiotic ointment, and then cover the wound area with a sterile gauze bandage and first-aid tape. Clean the wound area daily with soap and water and apply a fresh sterile bandage. For a minor laceration, remove the bandage after a couple of days to promote healing
We have that the time the earthquake occurred is mathematically given as
The <u>earthquake </u>occurred at =7:03:00 pm
<h3>Co-ordinates</h3>
Question Parameters:
A seismic recording station located 4000 <em>kilometers </em>from the epicenter
an earthquake received the first P-wave at 7:10:00 p.m. (h:min:s).
Generally
From t-x diagram, the x axis marks the distance of the <em>station </em>from the epicenter.
Hence we have that the P wave took 7 min to reach the station.
Arrival time of P and S wave is
dt=5 min 40 sec.
Therefore
The <u>earthquake </u>occurred at =7:03:00 pm
The S wave arrived at = 07:15:40 pm.
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Answer:
D. The frequency of the Ellis-van Creveld allele is 0.0447 in the isolated population and 0.0026 in the general population, which suggests that genetic drift has occurred in the isolated population.
Explanation:
If we assume that one gene is involved in Ellis-van Creveld syndrome and we name that gene with A, then the genotype of the syndrome would be aa.
In population 1, the frequency of the syndrome is 1/150000=0.0000066(it is the frequency of the aa gentotype)
In population 2, the frequency of the syndrome is 1/500=0.002
According to Hardy-Weinberg equilibrium
p2+2pq+q2=1 (p2 is the frequency of the dominant homozygous, 2pq is the frequency of heterozygous and q2 is the frequency of the recessive homozygous).
q or the frequency of the Ellis-van Creveld allele in Population 1 is 
=0.0026
q or the frequency of the Ellis-van Creveld allele in Population 2 is 
= 0.0447
