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abruzzese [7]
2 years ago
15

Using only an addition, how do you add eight 8’s and get the number 1000?

Mathematics
2 answers:
Contact [7]2 years ago
5 0

Answer: 8 added 125 times=1000. 888+88+8+8+8=1000.

Step-by-step explanation:

frosja888 [35]2 years ago
4 0

Answer:

888+88+8+8+8=1000

Step-by-step explanation:

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The number 3456 is divisible by wich single-digit number?
Gnesinka [82]

I'm assuming what you mean is what can you divide 3456 by to get a natural number.

First of all every number is divisible by 1.  

Every even number is divisible by 2, so since 3456 is an even number, it can be divided by 2.  That would equal 1728.

2456 can also be divided by 3, to get 1782.  

You can also divide it by 4, to get 865.

Divided by 6, it's 576.

Divided by 8, it's 432.

And lastly, 3456 divided by 9 is 384.

So, there isn't just one single-digit number you can divide 3456 by to get a natural number.  You can divide it by 1,2,3,4,6,8, and 9.

Hope that helps!

6 0
3 years ago
I need help on this plz
Fantom [35]
I’m timed on this I need help as well
4 0
3 years ago
1+2=21, 2+3=36,3+4=43,4+5=?
Anni [7]

1+2=21, 2+3=36, 3+4=43, 4+5=52.

4 0
3 years ago
Read 2 more answers
Three fourths of the fruit in a refrigerator
VashaNatasha [74]

Answer:32 fruits

Step-by-step explanation:

3/4=24/?

24÷3=8

8×4=32

4 0
3 years ago
A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0
3 years ago
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