Answer:
The horizontal shift is to the left by 2 units and the vertical shift is down 3 units for this function.
I hope I was able to help!
Step-by-step explanation:
Answer:
wwdwaDwadfafwfwefwfwefwefwefwefwefwweqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqqq
Step-by-step explanation:
Answer:
P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Step-by-step explanation:
Let P(n) be the proposition that 2n-1 ≤ n!. for n ≥ 3
Basis: P(3) is true since 2(3) - 1 = 5 < 3! = 6.
Inductive Step: Assume P(k) holds, i.e., 2k - 1 ≤ k! for an arbitrary integer k ≥ 3. To show that P(k + 1) holds:
2(k+1) - 1 = 2k + 2 - 1
≤ 2 + k! (by the inductive hypothesis)
= (k + 1)! Therefore,2n-1 ≤ n! holds, for every integer n ≥ 3.
11 more than five of a certain number would be written as 5x+11 and it is (means equal to) twenty more than two times that number, which would be 2x+20. So the equation would be
5x+11=2x+20
-2x -2x (get the x's on one side)
3x+11=20
-11 -11 (get the numbers on one side)
3x=9
/3 /3 (divide by 3, so you can get the x by itself)
X=3 (the number is 3)
Answer:
D
Step-by-step explanation:
when x=0, y=2
