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2 years ago

Can someone please help me with these equations? Thank you

Mathematics

1 answer:

e-lub [12.9K]2 years ago

8 0

H yes you have to do the c
N
Would be
Correct
Answer h

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the relationship between altitude and the boiling point is linear.AT an altitude of 8300ft 8300 ft , the liquid

mojhsa [17]

Complete Question

The relationship between altitude and the boiling point is linear. At an altitude of 8300ft, the liquid boils at 194.23 ° F

At an altitude of 4200 ft , the liquid boils at 202.02° F.

Write an equation giving the boiling point b of the liquid, in terms of altitude a in feet . feet . What is the boiling point of the liquid at 2600ft

Answer:

The equation is $y = -0.001943x + 210.3569$

At 2600ft the temperature is $y = 205.3051 \ °F$

Step-by-step explanation:

From the question we are told that

The temperature at 8300ft is 194.23 ° F

The temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

$m = \frac{ 202.2 - 194.23}{ 4200 - 8300}$

=> $m = 0.001943 ^o F / ft$

Generally the according to the point slope formula is

$y - y_1 = m(x -x_1 )$

=> $y - 194.23 = -0.001943 (x - 8300 )$

=> $y - 194.23 = -0.001943x + 16.1269$

=> $y = -0.001943x + 210.3569$

Now we are given from the question that x = 2600 ft

Then

$y = -0.001943(2600) + 210.3569$

=> $y = 205.3051 \ °F$

5 0

4 years ago

Subtract the following fractions.

yanalaym [24]

Answer:

22. 3/8

23. 3/5

24. 0

Step-by-step explanation:

turn the 1 into a fraction for each of the problems.

for 22. it would be 8/8 because also trying to make the denominators the same.

8/8 - 5/8 = 3/8

try 23 and 24 now!

5 0

3 years ago

Graph the function y = 15x – 31 + 1

marysya [2.9K]

Answer:

Step-by-step explanation:

Hi there!

The answer is at the attachment.

Have a nice day.

4 0

4 years ago

P(k)=a^k=2 3 4 find value of a that makes this is a valid probability distribution

Vesna [10]

Sounds like you're asked to find $a$ such that

$\displaystyle\sum_{k=2}^4\mathbb P(k)=\mathbb P(2)+\mathbb P(3)+\mathbb P(4)=1$

In other words, find $a$ that satisfies

$a^2+a^3+a^4=1$

We can factorize this as

$a^4+a^3+a^2-1=a^3(a+1)+(a-1)(a+1)=(a+1)(a^3+a-1)=0$

In order that $\mathbb P(k)$ describes a probability distribution, require that $\mathbb P(k)\ge0$ for all $k$ , which means we can ignore the possibility of $a=-1$ .

Let $a=y+\dfrac xy$ .

$a^3+a-1=\left(y+\dfrac xy\right)^3+\left(y+\dfrac xy\right)-1=0$
$\left(y^3+3xy+\dfrac{3x^2}y+\dfrac{x^3}{y^3}\right)+\left(y+\dfrac xy\right)-1=0$

Multiply both sides by $y^3$ .

$y^6+3xy^4+3x^2y^2+x^3+y^4+xy^2-y^3=0$

We want to find $x\neq0$ that removes the quartic and quadratic terms from the equation, i.e.

$\begin{cases}3x+1=0\\3x^2+x=0\end{cases}\implies x=-\dfrac13$

so the cubic above transforms to

$y^6-y^3-\dfrac1{27}=0$

Substitute $y^3=z$ and we get

$z^2-z-\dfrac1{27}=0\implies z=\dfrac{9+\sqrt{93}}{18}$
$\implies y=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}$
$\implies a=\sqrt[3]{\dfrac{9+\sqrt{93}}{18}}-\dfrac13\sqrt[3]{\dfrac{18}{9+\sqrt{93}}}$

6 0

4 years ago

Im doing a test review and I have no idea how to do this

Arisa [49]

Answer:

94.3?

Step-by-step explanation:

Well, the straight line is 180 degrees, there is a 90 degree square, and a 13 degree angle. So add them up and divide by three?

6 0

4 years ago