Question

Julia is playing a board game with a spinner that has 6 equally-sized segments: 2 1 3 6 4 5 If she spins a “6” then she gets to move forward 6 spaces and spin again. Then, if she spins a “2”, she wins. Assume that the outcome of one spin doesn't affect the outcome of future spins. а What is the probability that Julia spins a “6” followed by a “2”? Round your answer to two decimal places.

Answer 1

Using it's concept, it is found that there is a 0.0278 = 2.78% probability that Julia spins a “6” followed by a “2”.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem:

• There are 6 equally spaced segments, one of which represents 6, hence the probability that Julia spins a “6” is $P(A) = \frac{1}{6}$.

• The trials are independent, hence the probability that she spins a “2” is $P(B) = \frac{1}{6}$.

The probability of both events is given by:

$p = P(A)P(B) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36} = 0.0278$

0.0278 = 2.78% probability that Julia spins a “6” followed by a “2”.

More can be learned about probabilities at brainly.com/question/15536019