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DedPeter [7]
2 years ago
8

#6 i Find the value of each variable in the parallelogram. 11 14 C +5 d + 4

Mathematics
1 answer:
sergejj [24]2 years ago
8 0

Answer:

c=6
d=10

Step-by-step explanation:

d+4=14 and c+5=11

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If you charge $2,000 on a credit card today, how much will the
svet-max [94.6K]

Answer:

$5,674.30

Step-by-step explanation:

Use the Compound Amount formula:

A = P(1 + r/n)^(n*t), where r = APR as a decimal fraction = 0.1499

and n = 12 (compounded monthly).

Then A = $2,000(1 + 0.1499/12) )^(7*12)

             =  $2,000(1 +  0.0125)^84

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5 0
3 years ago
The angles of a quadrilateral measure 80, 100, 100, 80 in this order what kind of quadrilateral has this shape what attributes h
Harrizon [31]

Answer:

Isosceles trapezoid

Step-by-step explanation:

-An isosceles trapezoid is also sometimes called a convex quadrilateral.

-It properties include:

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8 0
4 years ago
Can somebody help me
Nuetrik [128]

Answer:

The second, and fourth choices are true.

Step-by-step explanation:

The symbol <  means less than  so the arrow will point to the LEFT.

Also -1/4 will not be a part of the solution. because the sign is less than.

Because the inequality is less than there will be an open circle at -1/4.

8 0
4 years ago
Use the coordinates to find the length of each side of the rectangle. Then find the perimeter. L(3,3), M(3,5), N(7,5), P(7,3)
larisa86 [58]
Length of legs:2,2,4,4, p=12
5 0
4 years ago
Read 2 more answers
If sine theta equals three over four, what are the values of cos θ and tan θ?
ankoles [38]

Answer:

Part 1) cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

cosine theta equals plus or minus square root of seven over 4

Part 2) tan(\theta)=(+/-)\frac{3}{\sqrt{7}}

tangent theta equals plus or minus three over square root of seven

or

tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}

tangent theta equals plus or minus three times square root of seven over seven

Step-by-step explanation:

we have that

The sine of angle theta is equal to

sin(\theta)=\frac{3}{4}

Is positive

therefore

The angle theta lie on the I Quadrant or in the II Quadrant

Part 1) Find the value of the cosine of angle theta

Remember that

sin^{2} (\theta)+cos^{2} (\theta)=1

we have

sin(\theta)=\frac{3}{4}

substitute and solve for cosine of angle theta

(\frac{3}{4})^{2}+cos^{2} (\theta)=1

cos^{2} (\theta)=1-(\frac{3}{4})^{2}

cos^{2} (\theta)=1-\frac{9}{16}

cos^{2} (\theta)=\frac{7}{16}

cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

cosine theta equals plus or minus square root of seven over 4

Part 2) Find the value of tangent of angle theta

we know that

tan(\theta)=\frac{sin(\theta)}{cos(\theta)}

we have

sin(\theta)=\frac{3}{4}

cos(\theta)=(+/-)\frac{\sqrt{7}}{4}

substitute

tan(\theta)=\frac{\frac{3}{4}}{(+/-)\frac{\sqrt{7}}{4}}

tan(\theta)=(+/-)\frac{3}{\sqrt{7}}

tangent theta equals plus or minus three over square root of seven

Simplify

tan(\theta)=(+/-)3\frac{\sqrt{7}}{7}

tangent theta equals plus or minus three times square root of seven over seven

4 0
3 years ago
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