Answer:
D is not a supported statement
Step-by-step explanation:
Let take them one by one:
A: from table: 0.57; in statement: 0.5
0.57 > 0.5 so this is supported
B: from table: 0.2+0.16=0.36; in statement: 1/3=0.33,
0.36>0.33 so this is supported
C: 0.07 is the least, so this is supported
D: the table DOES NOT show number of students, but proportions. So statement '7 students' IS NOT supported
E: from table 0.20 overslept. 0.2 < 1/4=0.25, so this is supported
8 is 1/6 of 8/6 = 1 1/3
125 is 5/10 of 625/10 = 62 1/2
32 is 4/10 of 128/10 = 12 4/5
Answer:
Step-by-step explanation:
This problem can be solved by using the expression for the Volume of a solid with the washer method
where R and r are the functions f and g respectively (f for the upper bound of the region and r for the lower bound).
Before we have to compute the limits of the integral. We can do that by taking f=g, that is
there are two point of intersection (that have been calculated with a software program as Wolfram alpha, because there is no way to solve analiticaly)
x1=0.14
x2=8.21
and because the revolution is around y=-5 we have
and by replacing in the integral we have
and by evaluating in the limits we have
Hope this helps
regards
Answer:
A rational number is a number able to be put into a fraction, an irrational number is not able to be. Therefore, when adding the two, the rational and the irrational will be irrational. For example, 2 is a rational number, and 1.8903 is irrational. If you add the two, you will get 3.18903, which is unable to be put into a fraction.