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boyakko [2]
3 years ago
10

There were 50 dogs and 30 of them died how many is left

Mathematics
1 answer:
Elis [28]3 years ago
3 0

If 50 dogs are alive and 30 die there are 20 left

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25 POINTS HELP ME PLEASE ​
d1i1m1o1n [39]

Answer:D

Step-by-step explanation:

Your first solution is to look at the 10x^2y in order to get 8 from ten you would need to subtract 2x^something y and there is only one answer with that

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PLEASE HELP FAST I NEED 100% Contractor 3 gives Mrs. Solar the following fee table showing her charges for the contract work. a)
NARA [144]

rate of change is the slope

slope = (y2-y1)/(x2-x1)

m= (180-120)/(3-2)

m = 60/1

m = 60

b.  point slope form

y-y1 = m(x-x1)

y-120 = 60 (x-2)


c see attached graph.  x>=0 since it is hours

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-6(x-5)-4(6x+4) =-76
slava [35]

Answer: x=3

Step-by-step explanation:

6 0
4 years ago
The circumference of a circle is 20π cm. What is the DIAMETER of the circle?
Sladkaya [172]

Answer:20cm

Step-by-step explanation:

Circumference=20π

Diameter=circumference ➗ π

Diameter=20π ➗ π

Diameter=20

Diameter=20cm

7 0
3 years ago
Paul has three cube-shaped boxes. Each box is a different size
qwelly [4]

Answer:

See explanation

Step-by-step explanation:

Paul has three cube-shaped boxes. Each box is a different size and they are stacked from the largest to the smallest. Some information about the boxes is given below.

  • The combined volume of the three boxes is 1,197 cubic inches.
  • The area of one face of the medium box is 49 square inches.
  • The volume of the smallest box is 218 cubic inches less than the volume of the medium box.

1. The medium box has the area of one face of 49 square inches, then

a^2=49\\ \\a=7\ inches

is the side length.

The volume of the medium box is

a^3=7^3=343\ in^3.

2. The volume of the smallest box is 218 cubic inches less than the volume of the medium box, then the volume of the smallest box is

343-218=125\ in^3.

Ib is the side length, then

b^3=125\\ \\b=5\ inches

The area of one face is

b^2=5^2=25\ in^2.

3. The volume of the largest box is

1,197-343-125=729\ in^3,

then if c is the side length,

c^3=729\\ \\c=9\ inches.

4. The total height of the stack is the sum of all sides lengths:

a+b+c=7+5+9=21\ inches

5. Find the surface area of each box:

  • small 6b^2=6\cdot 5^2=6\cdot 25=150\ in^2;
  • medium 6a^2=6\cdot 7^2=6\cdot 49=294\ in^2;
  • large 6c^2=6\cdot 9^2=6\cdot 81=486\ in^2.

In total, Paul needs

150+294+486=930\ in^2

of wrapping paper. He has 1,000 square inches, so Paul has enough paper to wrap all 3 boxes.

8 0
4 years ago
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