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2 years ago

Please see below!! Thank you so much in advance :)

Mathematics

1 answer:

stellarik [79]2 years ago

7 0

Answer:

a) x = -1.9, 1.05

b) x = -3, 0, 2

Explanation:

I hope it's correct

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The dimensions of a garden are 30' by 20'. If a model garden with the scale of 10' = 5'' is to be made, find the dimensions of t

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Answer:

15" by 10"

Step-by-step explanation:

Use a proportion.

10'/5" = 30"/x

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10x = 150

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2 years ago

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Step-by-step explanation:

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2 years ago

In a study, 36% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop

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Answer:

0.3907

Step-by-step explanation:

We are given that 36% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health.

i.e. $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

Formula : $P(x=r)=^nC_r p^r q ^ {n-r}$

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, $P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)$

$P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!} (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}$

$P(x\leq 3)=0.390748$

Hence the probability that when 11 adults are randomly selected, 3 or fewer are in excellent health is 0.3907

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2 years ago

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