n, n + 2, n + 4 - three consecutive even integers
the twice the sum of the second and third: 2[(n + 2) + (n + 4)]
twelve less than six times the first: 6n - 12
The equation:
2[(n + 2) + (n + 4)] = 6n - 12
2(n + 2 + n + 4) = 6n - 12
2(2n + 6) = 6n - 12 <em>use distributive property</em>
(2)(2n) + (2)(6) = 6n - 12
4n + 12 = 6n - 12 <em>subtract 12 from both sides</em>
4n = 6n - 24 <em>subtract 6n from both sides</em>
-2n = -24 <em>divide both sides by (-2)</em>
n = 12
n + 2 = 12 + 2 = 14
n + 4 = 12 + 4 = 16
<h3>Answer: 12, 14, 16</h3>
For 6 I think it was B I am not so sure. Its been a long time since i did triangles
Answer:
Because most kids dont like going to church.
Biggest is all nine's
smallest is 1 then zeroes
greatest
999999
smallest
10000
3/4 equals .75, and 60% equals .60. Therefore, we can set up an equation. .75=.60x, where x is the number we are looking for.
Divide each side by .60 to get the variable by itself. .75/.60= 1.25.
Hope this helped!!! :)
