Answer:

Step-by-step explanation:
Volume of water in the tank = 1000 L
Let y(t) denote the amount of salt in the tank at any time t.
Initially, the tank contains 60 kg of salt, therefore:
y(0)=60 kg
<u />
<u>Rate In</u>
A solution of concentration 0.03 kg of salt per liter enters a tank at the rate 9 L/min.
=(concentration of salt in inflow)(input rate of solution)

<u>Rate Out</u>
The solution is mixed and drains from the tank at the same rate.
Concentration, 
=(concentration of salt in outflow)(output rate of solution)

Therefore, the differential equation for the amount of Salt in the Tank at any time t:

Answer:
f(x) = 4x
Step-by-step explanation:
Verification:
f(2) = 4 x 2 = 8
f(3) = 4 x 3= 12
f(4) = 4x x 4 = 16
Answer:
C. = 69.5
Step-by-step explanation:
The median or the average between 80 and 59 is 69.5
Hope this helps! :)