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Temka [501]
3 years ago
13

Which set of side lengths form a right triangle?

Mathematics
1 answer:
k0ka [10]3 years ago
8 0

Answer:

50, 48, 14

Step-by-step explanation:

Go through them one by one. The side lengths of a triangle should all plug in to the formula a^2 + b^2 = c^2. The longest side is always c because it is the hypotenuse. The other two sides are interchangeable.

8^2+ 14^2 should equal 17^2.

That simplifies to

64+196=289

That can't be true because the units digits add to 10 instead of 9.

The same method applies to 3, 5, and 6 but from experience I know that this already isn't an option.

For 50, 48, and 14, you can divide everything by 2, resulting in 25, 24, and 7.

576+49 should equal 625.

That is true.

For 53, 48, and 24

576+2304 should equal 2809.

That isn't true, it equals 2880.

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Y=-4(x-2)2+4<br> what is the x intercept
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0 = -4(x -2)^2 +4 \\ -4(x -2)^2 +4 = 0 \\ -4(x -2)^2 = -4 \\ 4(x -2)^2 = 4 \\ (x-2)^2 = \frac{4}{4} \\ (x -2)^2 = 1 \\ x-2 = \pm \sqrt1 \\ x -2 = \pm 1 \\ x = \pm 1 +2

Solving for the Positive Square Root:

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Answer:

slope = - \frac{1}{3}

Step-by-step explanation:

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m = \frac{3-5}{8-2} = \frac{-2}{6} = - \frac{1}{3}

7 0
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