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yan [13]
3 years ago
6

How does burning fossil fuels cause an increase of carbon in the air?

Chemistry
2 answers:
mash [69]3 years ago
8 0

Answer:

Because burning a non-renewable resource that is not good for the atmosphere, will always cause some kind of chemical reaction to happen.

Examples of these reactions are...

  1. Acid rain, a very dangerous disaster.
  2. Global warming.
  3. Carbon increases.

Olin [163]3 years ago
7 0
When fossil fuels are burned, they release large amounts of carbon dioxide, a greenhouse gas, into the air. Greenhouse gases trap heat in our atmosphere, causing global warming. Already the average global temperature has increased by 1C
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Which of the following procedures involves a physical change in one of the substances?
defon

Answer:

D. Separating a salt solution by evaporating the water

Explanation:

B. Allowing a nail to rust is a chemical change.

Becuase once the nail rust it turns into flakes and therefore is no longer a nail.

C. building a model rocket propelled by mixing baking soda and vinegar

By mixing baking soda (a powder) into vinegar ( a Acid) it causes a explosion...

the baking soda dissolve into the acid.... This a chemical reaction

A.creating salt by reacting sodium metal and chlorine gas

Sodium is salt but it says.... Sodium metal..... chlorine gas Changes color and it has a strong odor... chlorine gas with sodium metal turns it into salt.... it doesnt stay a metal or a gas it CHANGES.....

so therefore its a Chemical change

When A object or substance changes form or it causes a exsplosion or reaction it is a chemical change.

D. Separating a salt solution by evaporating the water

For a physical change your object may change color or shape but its still the same object.

salt in water ... The salt dont dissolve it just salty water.

So seperating salt by evaporating the water is a physical change.

5 0
3 years ago
Read 2 more answers
A molecular biologist measures the mass of cofactor A in an average yeast cell. The mass is 96.15 pg . What is the total mass in
Morgarella [4.7K]

Given data:

Mass of cofactor A in an average yeast cell = 96.15 pg

Now:

1 picogram (pg) = 1*10^{-12} g

1 microgram (ug) = 1*10^{-6} g

Therefore, 1 pg = 1*10^{-6}ug

Mass of cofactor A in one yeast cell = 96.15 * 10^{-6} micro gram

Number of cells in the yeast colony = 105

Therefore, the total mass of cofactor A is given as:

Number of cells * mass of cofactor A per cell

= 105 cells * 96.15 *10^{-6} micro grams/cell = 1.009 * 10^{-2} micro grams

 

4 0
4 years ago
What is the correct Lewis structure for chloroform CHCI3
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Lewis structure for CHCl3

7 0
3 years ago
Complete and balance the following equation: S(s)+HNO3(aq)→H2SO3(aq)+N2O(g)(acidic solution)
meriva

Answer:- The balanced equation is, 2HNO_3(aq)+2S(s)+H_2O(l)\rightarrow N_2O(g)+2H_2SO_3(aq) .

Solution:- Oxidation number of S is increasing from 0 to 4 and so it is oxidation. Oxidation number of N is decreasing from 5 to 1 and so it is reduction.

We write the oxidation and reduction half equations and balance them. The given reaction is taking place in an acidic medium.

First of all we balance all the atoms other than H and O. Then oxygen is balanced by adding H_2O and hydrogen is balanced by adding H^+ . Charge is balanced by adding electrons.

To makes the electrons equal for both the half equations we multiply the equation/equations by appropriate numbers.

Oxidation half equation:

S(s)\rightarrow H_2SO_3(aq)

S is already balanced. To balance O, we need to add three water molecules to the left side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)

For balancing hydrogen, we need to add 4 hydrogen ions to the right side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)+4H^+(aq)

Now to balance the charge we need to add 4 electrons to the right side:

S(s)+3H_2O(l)\rightarrow H_2SO_3(aq)+4H^+(aq)+4e^-

Reduction half equation:

HNO_3(aq)\rightarrow N_2O(g)

To balance N, we need to multiply left side by 2:

2HNO_3(aq)\rightarrow N_2O(g)

For balancing oxygen, we need to add 5 water molecules to the right side:

2HNO_3(aq)\rightarrow N_2O(g)+5H_2O(l)

To balance hydrogen, we need to add 8 hydrogen ions to the left side:

2HNO_3(aq)+8H^+(aq)\rightarrow N_2O(g)+5H_2O(l)

Now, for charge balance, we need to add 8 electrons to the left side:

2HNO_3(aq)+8H^+(aq)+8e^-\rightarrow N_2O(g)+5H_2O(l)

First half equation has 4 electrons and second half equation has 8 electrons.

To make the electrons equal, we need to multiply oxidation half equation by 2:

2S(s)+6H_2O(l)\rightarrow 2H_2SO_3(aq)+8H^+(aq)+8e^-

Now we add both of these two half equations and cancel out common species. What we get on doing this is:

2HNO_3(aq)+2S(s)+H_2O(l)\rightarrow N_2O(g)+2H_2SO_3(aq)



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