Answer:
C.$4,300
Step-by-step explanation:
We are given that
Cost of truck=$19,000
Depreciation per year=$21,00
We have to find the salvage value.
Let salvage value=x
Formula:Depreciation per year=![\frac{C.P-salvage\;value}{number\;of\;years}](https://tex.z-dn.net/?f=%5Cfrac%7BC.P-salvage%5C%3Bvalue%7D%7Bnumber%5C%3Bof%5C%3Byears%7D)
Using the formula
Substitute the values then we get
![2100=\frac{19000-x}{7}](https://tex.z-dn.net/?f=2100%3D%5Cfrac%7B19000-x%7D%7B7%7D)
![2100\times 7=19000-x](https://tex.z-dn.net/?f=2100%5Ctimes%207%3D19000-x)
![14700=19000-x](https://tex.z-dn.net/?f=14700%3D19000-x)
![x=19000-14700](https://tex.z-dn.net/?f=x%3D19000-14700)
![x=4300](https://tex.z-dn.net/?f=x%3D4300)
Hence, the salvage value=$4,300
I think it would just be c(x) = 20,000 + 4x
Domain being [20,0000, infinity) because your cost will never be lower than 20,000