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3 years ago

Express each rational number as a fraction or mixed number in simplest form. 25

Mathematics

1 answer:

Sloan [31]3 years ago

4 0

25 expressed as a mixed number is just 25

-Hunter

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Consider a nine -year moving average used to smooth a time series that was first recorded in 1961. a. Which year serves as the f

kirill [66]

Answer:

a. 1965

b. 8 years

Step-by-step explanation:

For answers to questions like these it can work to consider the smallest possible dataset.

<h3>Dataset</h3>

For our purpose, consider the 9 years/values to be averaged to be ...

1, 2, 3, 4, 5, 6, 7, 8 ,9

<h3>Observations</h3>

a. The center value of the data set is 5. Its number is 5-1=4 more than the first one.

The first centered value is from the year 1961 +4 = 1965.

b. The 4 values at the beginning, and the 4 values at the end do not have a corresponding "average" value. That is, 4+4 = 8 values in the series are lost with respect to the number of average values.

8 years of values are lost.

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2 years ago

Pls help! will give brainlist!

lara31 [8.8K]

It couldn’t be anything else but C line reflection i’m assuming

4 0

3 years ago

Read 2 more answers

What is the value of k in the function ƒ(x) = 112 - kx if ƒ(-3) = 121?

Nana76 [90]

I hope this helps you

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4 years ago

What is the fraction to this equation 0.020<br><br><br> Pls help fast.

sukhopar [10]

Answer: 1/50

Step-by-step explanation:

0.020 = 20/1000 = 1/50

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3 years ago

Read 2 more answers

MARKING AS BRAINLIEST!!

devlian [24]

Answer: They are inverses of each other

============================================================

Explanation:

We need to check two things:

f(g(x)) = x
g(f(x)) = x

If both of those equations are true, then f and g are inverses of each other.

----------------

Part 1

$f(x) = -3x-12\\\\f(g(x)) = -3( g(x) )-12\\\\f(g(x)) = -3\left( \frac{-12-x}{3} \right)-12\\\\f(g(x)) = 12+x-12\\\\f(g(x)) = x\\\\$

So far, so good. Now we need to check the other equation mentioned.

------------------

Part 2

$g(x) = \frac{-12-x}{3}\\\\g(f(x)) = \frac{-12-( f(x) )}{3}\\\\g(f(x)) = \frac{-12-( -3x-12 )}{3}\\\\g(f(x)) = \frac{-12+3x+12}{3}\\\\g(f(x)) = \frac{3x}{3}\\\\g(f(x)) = x\\\\$

That works out as well. Both equations mentioned are true, which confirms the two original functions are inverses of one another.

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3 years ago