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olganol [36]
3 years ago
14

Express each rational number as a fraction or mixed number in simplest form. 25

Mathematics
1 answer:
Sloan [31]3 years ago
4 0

25 expressed as a mixed number is just 25

-Hunter

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A first number plus twice a second number is 13. Twice the first number plus the second totals 14. find the numbers​
sashaice [31]

Answer:

the first number is 5 the second number is 4

Step-by-step explanation:

first number = x

second number = y

X+2y=13 given this isolate x  x = 13-2y

2x+y=14 substitute 13-2y for x

2(13-2y)+y=14

26-4y+y=14

-3y=-12

y=4 taking this number substitute into either equation above

x+2(4)=13

x+8=13

x=5

4 0
3 years ago
Question 3 of 10 Select the expression that is equivalent to (x + 4)^2.​
sesenic [268]

Answer:

Step-by-step explanation:

Hhuiodkrnf

3 0
3 years ago
Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.
dusya [7]

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

5 0
2 years ago
Read 2 more answers
The difference of two numbers is 8. If the sum of the smaller number and the square of the larger number is 148, what is the sma
Mice21 [21]

Answer:

140

8 minuses by 148 is 140

4 0
3 years ago
PLEASE SHOW WORK
CaHeK987 [17]

(C)

Step-by-step explanation:

The volume of the conical pile is given by

V = \dfrac{\pi}{3}r^2h

Taking the derivative of V with respect to time, we get

\dfrac{dV}{dt} = \dfrac{\pi}{3}\dfrac{d}{dt}(r^2h)

\:\:\:\:\:\:\:= \dfrac{\pi}{3}\left(2rh\dfrac{dr}{dt} + r^2\dfrac{dh}{dt}\right)

Since r is always equal to h, we can set

\dfrac{dr}{dt} = \dfrac{dh}{dt}

so that our expression for dV/dt becomes

\dfrac{dV}{dt} = \dfrac{\pi}{3}\left(3r^2\dfrac{dh}{dt}\right)

\:\:\:\:\:\:\:= \pi r^2\dfrac{dh}{dt}

Solving for dh/dt, we get

\dfrac{dh}{dt} = \dfrac{1}{\pi r^2}\dfrac{dV}{dt}

\:\:\:\:\:\:\:= \dfrac{1}{9\pi\:\text{m}^2}(36\:\text{m}^3\text{/s})

\:\:\:\:\:\:\:= \dfrac{4}{\pi}\:\text{m/s}

7 0
3 years ago
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