Answer:
Yes
Step-by-step explanation:
Given,
Population mean Z = 600
Sample mean, µ = 586.50
Size of the sample, n = 10
Standard deviation, σ = 26.77
The testing hypothesis is,
Null hypothesis = µ<600
Alternative hypothesis = µ≥600
The test statistics is the calculated value of Z,
(Z- µ)/(σ/√n)
= (600-586.50)/(26.77/√10)
= (13.5*3.1623)/26.77
= 42.691/26.77
= 1.5947
And at 5% level of significance, the table value of Z = 1.644
Here, calculated Z<Table value of Z, so we accept the null hypothesis.
So, the null hypothesis is accepted. The mean value of the laptop is less than 600.
