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vlada-n [284]
2 years ago
10

Solve the inequality 5(2x+1)<10​

Mathematics
2 answers:
Mashcka [7]2 years ago
7 0

Answer:

x<1/2

Step-by-step explanation:

Hope this helps!

nevsk [136]2 years ago
5 0

Answer:

5*(2*x+1)-+10)<0

10x-5=5•2x-1

5•(2x-1)<0

divide both sides by 5

divide both sides by 2

x-1/2<0

add 1/2 on both sides x<1/2

so, x<1/2

Step-by-step explanation:

hope it helps

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2 years ago
7x-5=8(x+3) solve for x​
Harlamova29_29 [7]

Answer:

The value of x is -29.

Step-by-step explanation:

We are given an algebraic equation and have one goal: solve for x. We can use simplifying techniques as well as addition and subtraction to solve this equation.

\text{7x - 5 = 8(x + 3) \ \ \ Distribute the 8 throughout the parentheses.}\\\text{7x - 5 = 8x + 24 \ \ \ \ Subtract 7x from both sides.}\\\text{-5 = x + 24 \ \ \ \ \ \ \ \ \ \ Flip the equation.}\\\text{x + 24 = -5 \ \ \ \ \ \ \ \ \ \ Subtract 24 from both sides.}\\\small\boxed{\bold{{x = -29}}}

Now that we have solved for x, we can plug in -29 to see if we get a true statement.

\text{7(-29) - 5 = 8(-29 + 3)}\\\text{-203 - 5 = -232 + 24}\\\text{-208 = -208} \ \checkmark

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6 0
3 years ago
A perpendicular bisector, , is drawn through point C on .
Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)

The coordinates of C are (2,4).

Line AB has a slope of:m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : m_2=-\frac{5}{2}

The point slope form of a line is given by:

y-y_1=m(x-x_1)

The slope of line CD is -\frac{5}{2} and the line passing through the point (2,4), the equation of line CD can be written as:

y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9       .... (1)

The equation of CD is y=-\frac{5}{2}x+9

In order to find the x-intercept, put y=0.

0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

y=-\frac{5}{2}(-52)+9=139

Put x=-20 in eq(1).

y=-\frac{5}{2}(-20)+9=59

Put x=32 in eq(1)

y=-\frac{5}{2}(32)+9=-71

Put x=-54 in eq1).

y=-\frac{5}{2}(-54)+9=144

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

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