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disa [49]
2 years ago
14

Activity #2

Mathematics
2 answers:
loris [4]2 years ago
7 0

Answer:

Step-by-step explanation:

1. The sum of 5 and 8. _5+ 8 _____   =13

2. The product of 3 and 4.   _3*4____ = 12

3. The square of 8. __8^2____   = 64

4. The sum of a number and 3. __x+3___

5. 4 times a number subtracted from 78. _78-4x_____

vesna_86 [32]2 years ago
4 0

Answer:

thats all i know

Step-by-step explanation:

1.5+8

2.3×4

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David's : y = 12,350 - (240x)
Amanda's : y = 12,350 + (240x)

David's equation is correct, because their spending will be multiplied by the number of months and then subtracted from their savings


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Step-by-step explanation:

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3 years ago
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(05.08)Solve for x: 7 over 8 minus 1 over x equals 3 over 4.
NemiM [27]

If you are asking 7/8 - 1/x= 3/4,

first put 3/4 to 6/8 to make it easier.

Move the 7/8 over to the right. You will get 1/x=-1/8.

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Check=7/8 - 1/8=6/8

It checks out.

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3 years ago
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Find the derivative of the following. please show the steps when you answer :1) f(x) = 8xe^x2) y= 5xe^x^43) f(x)= x^8+5/x4) f(t)
borishaifa [10]

Answer:

Since,

\frac{d}{dx}x^n = nx^{n-1}

\frac{d}{dx}(f(x).g(x)) = f(x).\frac{d}{dx}(g(x)) + g(x).\frac{d}{dx}(f(x))

\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x).f'(x) - f(x) g'(x)}{(g(x))^2}

1) y = 8x e^x

Differentiating with respect to x,

\frac{dy}{dx}=8( x \times e^x + e^x) = 8(xe^x + e^x) = 8e^x(x+1)

2) y = 5x e^{x^4}

Differentiating w. r. t x,

\frac{dy}{dx}=5(x\times 4x^3 e^{x^4}+e^{x^4})=5e^{x^4}(4x^4+1)

3) y = x^8 + \frac{5}{x^4}

Differentiating w. r. t. x,

\frac{dy}{dx}=8x^7 - \frac{5}{x^5}\times 4 = 8x^7 - \frac{20}{x^5}=\frac{8x^{12}-20}{x^5}

4) f(t) = te^{11}-6t^5

Differentiating w. r. t. t,

f'(t) = e^{11} - 30t^4

5) g(p) = p\ln(2p+3)

Differentiating w. r. t. p,

g'(p) = p\frac{1}{2p+3}(2) + \ln(2p+3) = \frac{2p}{2p+3}+\ln(2p+3)

6) z = (te^{6t}+e^{5t})^7

Differentiating w. r. t. t,

\frac{dz}{dt}=7(te^{6t}+e^{5t})^6 ( 6te^{6t}+e^{6t} + 5e^{5t})

7) w =\frac{2y + y^2}{7+y}

Differentiating w. r. t. y,

\frac{dw}{dy} = \frac{(7+y)(2+2y)-(2y+y^2)}{(7+y)^2} = \frac{14 + 2y + 14y +2y^2 - 2y - y^2}{(7+y)^2}=\frac{14+14y+y^2}{(7+y)^2}

7 0
3 years ago
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