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Semenov [28]
2 years ago
8

PLEASE ANSWER THE BLANKS PLEASE AND USE AN ANSWER FROM THE PARENTHESES BESIDE THE QUESTION, I'M GIVING BRAINLIEST IF YOU ANSWER

CORRECTLY!! (literally all u gotta do is tell me what number fits the blank lol)
--
Four identical cubes are joined to make a new shape.

| Answer the questions below to find the new shape’s surface area. |
v v

1a. There are |___| squares on the surface of the figure.
(10, 16, 18, 21)

1b. Each square has an area of |___| in².
(6, 12, 24, 36)

1c. So, the surface area of the figure is |___| in².
(54, 324, 576, 648)

Mathematics
1 answer:
sleet_krkn [62]2 years ago
5 0

Answer 1a 18 1b 36 1c 648

1a : if you look at the shape you will see its made of squares. I counted the squares, its 18.

1b : one side is 6 in. since its a square all sides are equal. so multiply 6 by 6 to get 36.

1c : this one is easy. We take the number of squares across the surface (18) by the area of each square (36) it is 648.

Also sorry I didn't make this clearer earlier.

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Find the volume of the region bounded above by the paraboloid z equals 3 x squared plus y squared and below by the square R: min
RideAnS [48]

Answer:

V=5.333cubit unit

Step-by-step explanation:

this problem question, we are required to evaluate the volume of the region bounded by the paraboloid z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1

The question can be interpreted as z = f(x, y) = 3x² + y² and the square r: -1≤ x ≤ 1, -1 ≤ y ≤ 1 and we are told to evaluate the volume of the region bounded by the given paraboloid z

The volume V of integral evaluated along the limits of x and y for the 2-D figure, can be evaluated using the expression below

V = ∫∫ f(x, y) dx dy then we can now substitute and integrate accordingly.

CHECK THE ATTACHMENT BELOW FOR DETAILED EXPLATION:

5 0
4 years ago
Is 49.20 greater than 49.22
Helen [10]
49.22 is greater than 49.20
6 0
3 years ago
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Which of the following values could the number 500,000 be composed of?
OverLord2011 [107]

50000 tens

5000hundreds

How?

  • 1ten=10

50000 tens:-

\\ \sf\longmapsto 50000(10)=500000

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8 0
3 years ago
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In the figure, AB║CD and ∠EIA is congruent to ∠GJB Complete the following statements to prove that ∠IKL is congruent to ∠DLH.
Finger [1]

Here it is given that AB || CD

< EIA = <GJB

Now

∠EIA ≅ ∠IKC and ∠GJB is ≅ ∠ JLD (Corresponding angles)

∠EIA  ≅ ∠GJB then ∠IKC ≅ ∠ JLD (Substitution Property of Congruency)

∠IKL + ∠IKC 180° and ∠DLH +  ∠JLD =180° (Linear Pair Theorem)

So

m∠IKL + m∠IKC = 180°       ....(1)

But ∠IKC  ≅ ∠JLD

m∠IKC = m∠JLD (SUBTRACTION PROPERTY OF CONGRUENCY)

So we have

m∠IKL + m∠JLD = 180°

∠IKL and ∠JLD are supplementary angles.

But ∠DLH and ∠JLD are supplementary angles.

∠IKL ≅ ∠DLH (CONGRUENT SUPPLEMENTS THEOREM)

7 0
3 years ago
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