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3 years ago

For what value of the variable will b the value of 3−5c be 1 less than the value of 1−c?

Mathematics

1 answer:

Crank3 years ago

7 0

Answer:

c = 3/4

Step-by-step explanation:

Lets set up an equation.

You can get

3-5c + 1 = 1-c to show that it is one less.

now we can solve it.

So by combining like terms, we get:

4-5c = 1-c

that then becomes:

3-5c = -c

--> 3 = 4c

--> c = 3/4

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Answer:

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Step-by-step explanation:

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4 years ago

As a store manger you would like to find out the average time it takes to unload the truck which delivers the merchandise for yo

Georgia [21]

Answer:

The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

Step-by-step explanation:

We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.

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95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.9}{2} = 0.975([tex]t_{975}$ ). So we have T = 2.0322

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The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes

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4 years ago

Read 2 more answers

HELPPPP JUST 2 QUESTIONS BASED ON PYTHAGOREAN THEOREM AND IM CONFUSED HELPPPP

Anna007 [38]

9514 1404 393

Answer:

3. no; does not have the correct ratio to other sides

4. (1; right), (2; obtuse), (3; right)

Step-by-step explanation:

3. There are a couple of ways you can go at this.

a) the ratio of sides of a 30°-60°-90° right triangle (half an equilateral triangle) is 1 : √3 : 2. Here, the ratio of sides is ...

(√30/2) : √15 : √30 = 1 : √2 : 2 . . . . MQ is not the height

b) the height is perpendicular to the base, so if MQ were the height, the sides of the triangle would satisfy the Pythagorean theorem:

LQ² +MQ² = LM²

(√30/2)² +(√15)² = (√30)²

30/4 +15 = 30

22.5 = 30 . . . . NOT TRUE

The length MQ cannot be the height of ∆LMN. (It is too short.)

4. To see if these lengths form a right triangle, you can test them in the Pythagorean theorem relation. In the attached we have reformulated the equation so it gives a value of 0 if the triangle is a right triangle:

c² = a² +b² . . . . . Pythagorean theorem

c² -a² -b² = 0 . . . . rewritten

If the value of c² -a² -b² is not zero, then the side lengths do not form a right triangle. The attached shows this math performed by a graphing calculator. The results are ...

right triangle
not a right triangle — long side is too long, so the triangle is obtuse
right triangle

_____

Additional comment

The attached table demonstrates an artifact of computer arithmetic. Not all numbers can be represented exactly in a computer, so a difference that is expected to be zero using exact arithmetic may be slightly different from zero when computed by a computer or calculator. Here, we see a difference of about 6×10^-14 when zero is expected. On most calculators (with 10, or 12 displayed digits), this would be displayed as 0.

The same calculation done "by hand" gives ...

(√425)² -5² -20² = 425 -25 -400 = 0 . . . Triangle 1 is a right triangle