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3 years ago

15

An automobile tire has a diameter of about 1.7. What is the circumference

1 answer:

lilavasa [31]3 years ago

3 0

Answer:

r = 0.85 ft
C = 5.3407075111026 ft
A = 2.2698006922186 ft²

Agenda:

r = radius
C = circumference
A = area
π = pi = 3.1415926535898
<span>√ = square root
</span>
Formula:
Circumference of a circle:

C = 2πr = πd

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Q#2 Graph the relation in the table.Then use the vertical-line test.Is the relation a function

tresset_1 [31]

The graph of the relation between x and y is as shown in attached figure

By applying the vertical line test we find that the relation is not a function because there are two points which are (1,-1) , (1,3) have the same value of x with different values of y which contradicts with with the rule of function.

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(-5/2,-4)

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Find a rational number halfway between 7/8 and 6/7

algol [13]

<h3>Answer: 97/112</h3>

================================================

How to get this answer:

Midpoint formula: (A+B)/2 = C

A and B are the endpoints with C as the midpoint

A = 7/8

B = 6/7

A+B = 7/8 + 6/7

A+B = 49/56 + 48/56

A+B = (49+48)/56

A+B = 97/56

(A+B)/2 = (97/56) divided by 2

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(A+B)/2 = (97*1)/(56*2)

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3 years ago

Write the sentence as an equation.<br><br> 38 less than the quantity f times 235 equals 44

Dimas [21]

Answer:

235(f - 38) = 44

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A consumer products company found that 44% of successful products also received favorable results from test market research, w

Korolek [52]

Answer:

0.80
0.289
0.20
0.711

Step-by-step explanation:

Given:

$P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11$

The rule of total probability states that:

$P(A) = P(A\cap B) + P(A\cap B^{c})$

Compute the individual probabilities as follows:

$P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57$

$P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43$

$P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55$

$P(F^{c})=1-P(F)\\=1-0.55\\=0.45$

Conditional probability of an event A given B is:

$P(A|B)=\frac{P(A\cap B)}{P(B)}$

Compute the value of $P(S|F)$ :

$P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80$

Compute the value of $P(S|F^{c})$

$P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289$

Compute the value of $P(S^{c}|F)$

$P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20$

Compute the value of $P(S^{c}|F^{c})$

$P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711$

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3 years ago