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levacccp [35]
3 years ago
13

28 g of iron shot is added to a graduated cylinder containing 40cm of water. The water level rises to the 44cm mark. From this i

nformation, calculate the density of iron.
Mathematics
1 answer:
Aneli [31]3 years ago
6 0

\huge\fbox{Answer ☘}

Volume of water displaced = Volume of shape

‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎\bold{⇢ ( \:44 \:- \:40\: ) \:mL}\\\bold{⇢ 4 \:mL}

Weight = 28 g

\bold\blue{density =  \frac{mass}{volume}}  \\  \\ \pink{ ⇢ \cancel \frac{28}{4}  }\\  \\  \pink{⇢ 7 \: g \: ml {}^{ - 1}}

hope helpful ~

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Answer:

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Step-by-step explanation:

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Which number(s) below belong to the solution set of the inequality? Check all that apply.
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1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é: a) r = 6 b) r = 7 c) r = 9 d
Maslowich

Answer:

1) b) r = 7

2) e) 82

Step-by-step explanation:

Progressão aritmética:

Em uma progressão aritmética, a diferença entre termos consecutivos é sempre a mesma, chamada de razão.

O n-ésimo termo de uma PA é dado por, tomando o primeiro termo como referência:

a_n = a_1 + (n-1)r

Tomando o m-ésimo termo como referência, tem-se que:

a_n = a_m + (n-m)r

1) Se o 5o e o 9-o termos de uma PA são, respectivamente, 40 e 68, então a razão r da progressão é:

a_5 = 40, a_9 = 68. Então:

a_n = a_m + (n-m)r

68 = 40 + 4r

4r = 28

r = \frac{28}{4} = 7

Então a resposta correta é dada pela alternativa b.

2) Inserindo-se 6 números entre 72 e 107, de modo que a sequência (72, a2, a3, a4, a5, a6, a7 ,107) seja uma progressão aritmética, tem-se a3 igual a:

O primeiro termo é a_1 = 72 e o oitavo termo é a_8 = 107. Com isso, é possível encontrar a razão.

a_n = a_1 + (n-1)r

107 = 72 + 7r

7r = 35

r = \frac{35}{7} = 5

Então, o terceiro termo é:

a_3 = a_1 + 2r = 72 + 2(5) = 82

Logo, a resposta correta é dada pela alternativa e.

5 0
3 years ago
How long does it take for the account to be worth about $750?
pochemuha

Answer:

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Step-by-step explanation:

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