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larisa [96]
2 years ago
6

How much bigger is the largest bowl than the smallest bowl?

Mathematics
2 answers:
dmitriy555 [2]2 years ago
6 0

Answer:

5/8

Step-by-step explanation:

The biggest bowl Mr. Ramsey bought is 7/8, and the smallest is 2/8.

Thus, 7/8 - 2/8 = 5/8 quarts.

Sati [7]2 years ago
5 0

Answer:

5/8

Step-by-step explanation:

We see that the largest bowl size is 7/8, and that the lowest size is 2/8, from the data from the x plot.

Since these are similar fractions with the same denominator, we can subtract them. 7/8-2/8=5/8.

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Consider the following probability distribution function of the random variable X which represents the number of people in a gro
Troyanec [42]

Answer:

(a) 3.55

(b) 3.45 and 1.86

(c) 0.25

(d) 0.016

Step-by-step explanation:

The random variable <em>X</em> denotes the number of people in a group (party) at a restaurant.

(a)

The formula to compute the mean is:

\mu=\sum {x\cdot P(X=x)}

Consider the Excel sheet attached.

The mean is, 3.55.

(b)

The formula to compute the variance is:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}

Consider the Excel sheet attached.

Compute the variance as follows:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}\\\\=16.05-(3.55)^{2}\\\\=3.4475\\\\\approx 3.45

The variance is, 3.45.

Compute the standard deviation as follows:

\sigma=\sqrt{\sigma^{2}}\\\\=\sqrt{3.45}\\\\=1.85742\\\\\approx 1.86

The standard deviation is, 1.86.

(c)

Compute the probability that the next party will be over 4 people as follows:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\=0.10+0.05+0.05+0.05\\\\=0.25

Thus, the probability that the next party will be over 4 people is 0.25.

(d)

Compute the probability that the next three parties will each be over 4 people as follows:

It is provided that the three parties are independent.

P (Next 3 parties will be each over 4) = [P (X > 4)]³

                                                           =(0.25)^{3}\\=0.015625\\\approx 0.016

Thus, the probability that the next three parties will each be over 4 people is 0.016.

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3 years ago
A graphic designer chose a base font size and represented it as 1 on the scale. She then listed some consecutive scale sizes. Tw
Flauer [41]

Answer: 1.6464

Step-by-step explanation: I think.

4 0
3 years ago
-27+(-21)= must show work
Anarel [89]

Step-by-step explanation:

- 27 - 21 \\  =  - 48

8 0
3 years ago
Eric has 130 coins consisting of nickels and quarters the coins combined value comes to 15.90
just olya [345]

Answer:

A) N + Q = 130

B) .05N + .25Q = 15.90

Multiplying equation A by -.05 equals

A) -.05N -.05Q = -6.50  then adding this to B)

B) .05N + .25Q = 15.90  Equals

.20Q = 9.40

Quarters = 47

Nickels = 83

.05*83 + .25*47 = 4.15 + 11.75 = 15.90

Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
A coin is tossed $9$ times, and at least $7$ of the tosses were heads. How many different sequences of tosses could there have b
melamori03 [73]

Answer:

  • <u>46</u>

Explanation:

<u>1. Number of sequences with exactly seven heads:</u>

  • First head can go in 9 different positions
  • Second head can go in 8 different positions
  • Third head can go in 7 different positions
  • Fourth head can go in 6 different positions
  • Fifth head can go in 5 different positions
  • Sixth head can go in 4 different positions
  • Seventh head can go in 3 different positions

That gives: 9×8×7×6×5×4×3

Since all the heads are equivalent, you have repetitions that are not different. Then, you must discount the combinations that are equivalent.

In how many ways seven heads can be arranged? 7×6×5×4×3×2×1

Then, you must divide 9×8×7×6×5×4×3 by 7×6×5×4×3×2×1.

  • That is: 9 × 8 / 2 = 36 different ways of tossing seven heads

<u>2. Number of sequences with exactly eight heads:</u>

Following the same reasoning:

  • 9×8×7×6×5×4×3×2 divided by 8×7×6×5×4×3×2×1 = 9

  • That is 9 different ways of tossing eight heads.

<u>3. Number of sequences with exactly nine heads</u>

That is only one way: when all the tosses are heads: 1

<u>4. Number of sequences with at least seven heads</u>

Add the combinations of having exactly seven heads, eight heads and nine heads:

  • 36 + 9 + 1 = 46 ← answer
5 0
3 years ago
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