He could have rolled a 6 on the second roll without rolling a 6 on the first roll, the first roll had ZERO effect on the second one to be able to change what he would roll
Multiply entire equation by (x-2)(x+1) to get rid of the denominators That would lead to X(x+1)+(x-1)(x-2)=-1(x-2)(x+1) Finally, using distributive property and foil, you would get x^2+x+x^2-3x+2=(-x^2+x+2).2x^2-2x+2=-x^2+x+23x^2-3x=0 3x(x-1)x=0 and x=1
