Answer:
68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Step-by-step explanation:
The lengths of a lawn mower part are approximately normally distributed
Standard deviation =
We are supposed to find What percentage of the parts will have lengths between 3.8 in. and 4.2 in . i.e. P(3.8<x<4.2)
Formula : 
At x = 3.8
Z=-1
Refer the z table for p value
p value =0.1587
At x =4.2
Z=1
Refer the z table for p value
p value =0.8413
P(3.8<x<4.2)=P(x<4.2)-P(x<3.8)=0.8413-0.1587=0.6826
So, 68.26% of the parts will have lengths between 3.8 in. and 4.2 in.
Answer:
There is one solution and that answer is mixed number form 1 5/7 or exact form 12/7
Step-by-step explanation:
In:mi
2 = 30
x = 120
2/30=x/120
(Cross Multiply)
30x= 240
30x/30=240/30
X=8
d=rt
divide by r on both sides
d/r = t
300/60 =t
5=t
t=5 hours
d=rt
d/t =r
250/4.5 =r
55.5555555=r
55 5/9 miles per hour
Equation #1:
|2x - 3| = 17
The first solution is
2x - 3 = 17
2x = 17 + 3 = 20
x = 10
The second solution is
3 - 2x = 17
-2x = 17 - 3 = 14
x = -7
The solutions are x = 10 or x = -7.
Equation #2:
|5x + 3| = 12
The only solution is
5x + 3 = 12
5x = 12 - 3 = 9
x = 9/5
Let us examine the given answers.
a. Equation #1 and #2 have the same number of solutions.
FALSE
b. Equation @1 has more solutions than Equation #2.
TRUE
c. Equation #1 has fewer solutions than equation #2.
FALSE
d. None of the statements a,b, or c apply.
FALSE
Answer: b.
