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soldier1979 [14.2K]
2 years ago
15

Answer number 14 please

Mathematics
1 answer:
ale4655 [162]2 years ago
4 0
1 7/12 gallons

5/6 gallons = 1/4 minutes

5/6+3/4= 10/12, 1/4+3/4 = 4/4

19/12 gallons = 4/4 minutes

19/12 = 1 7/12
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Explain how to verify that 3(2x + 5) = 9 + 3x and x = –2 are equivalent equations.
aniked [119]

3 times (2x + 5) is 6x + 15.

6x + 15 = 9 + 3x.

Group by like terms. 6 = -3x

Divide to get x by itself. 6/-3 = -2

Thus -2 = x

6 0
3 years ago
In 1982 Abby’s mother scored at the 93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the
oksian1 [2.3K]

Answer:

The percentle for Abby's score was the 89.62nd percentile.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation(which is the square root of the variance) \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Abby's mom score:

93rd percentile in the math SAT exam. In 1982 the mean score was 503 and the variance of the scores was 9604.

93rd percentile. X when Z has a pvalue of 0.93. So X when Z = 1.476.

\mu = 503, \sigma = \sqrt{9604} = 98

So

Z = \frac{X - \mu}{\sigma}

1.476 = \frac{X - 503}{98}

X - 503 = 1.476*98

X = 648

Abby's score

She scored 648.

\mu = 521 \sigma = \sqrt{10201} = 101

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{648 - 521}{101}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

The percentle for Abby's score was the 89.62nd percentile.

3 0
3 years ago
Find y' by implicit differentiation √x +√y =1
AleksandrR [38]
Differentiate both sides with respect to x

\frac{d}{dx}(x^{\frac{1}{2}} + y^{\frac{1}{2}}) = \frac{d}{dx}(1)\\\\ \frac{1}{2x^{\frac{1}{2}}} + \frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = 0\\\\\frac{1}{2y^{\frac{1}{2}}}\frac{dy}{dx} = -\frac{1}{2x^{\frac{1}{2}}}\\\\\frac{1}{2\sqrt{y}}\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \\\\\frac{dy}{dx} = -\frac{1}{2\sqrt{x}} \times 2\sqrt{y}\\\\\frac{dy}{dx} = -\frac{\sqrt{y}}{\sqrt{x}} \\\\\boxed{\bf{y'= -\frac{\sqrt{y}}{\sqrt{x}}}}
5 0
3 years ago
Which statement best explains whether the table represents a linear or nonlinear function?
Leni [432]

 the bush shelter

can help you well try this method


6 0
4 years ago
Read 2 more answers
You estimate that a tree is 45 ft tall. It is actually 58 ft tall.
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You are 13 feet below from where you measured to where it actually is.
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