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KonstantinChe [14]
2 years ago
11

PROJECT: GEOMETRIC FIGURES IN THE COORDINATE PLANE

Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer:

1,Point C (0, 2)

2, Scalene triangles are triangles with three sides of different lengths. ... For example, a triangle with side lengths of 2 cm, 3 cm, and 4 cm would be a scalene triangle. A triangle with side lengths of 2 cm, 2 cm, and 3 cm would not be scalene, since two of the sides have the same length

3, EFGH is a cyclic quadrilateral .

Step-by-step explanation:

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y=1/7.50x+40

Step-by-step explanation:

I doubled checked myself on desmos and it worked. You start at 40$ because you pay that no matter what. For each one they buy the price goes up by 7.50$.

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Which expression is equivalent to the following complex fraction?
andrezito [222]

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The same thing but with y

Step-by-step explanation:

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Read 2 more answers
Factor the expression.
yanalaym [24]

Answer:

3(5n -6)

Step-by-step explanation:

15n -18

Both 15 and 18 can be divided by 3

Factor out a 3

3(5n -6)

4 0
3 years ago
How many pairs of numbers have a difference of 12
makvit [3.9K]
An infinite set of numbers have this characteristic.  Some examples:
0, 12
1, 13
2, 14
2.5, 14.5
Pick any number, add 12 to it, and the numbers you started with and ended with are your pair of numbers.

Hope this helps!
5 0
3 years ago
Without multiplying all the terms, verify these equalities. a) 10!= 6!7! b) 10!=7!5!3! c) 16!= 14!5!2! d) 9!=7!3!3!2!
Romashka-Z-Leto [24]

Answer:

a)10! = 6×5×4×3×2 ×7!

10! = 6! 7! (Verified)

b)10! = 3! × 5! × 7! = 7!5!3! (Verified)

c)16! = 2! × 5! × 14!

16! = 14!5!2! (Verified)

d)9! = 3! × 3! ×2! × 7!

9! = 7!3!3!2! (Verified)

Step-by-step explanation:

a) 10!= 6!7!

10! = 10×9×8×7!

Reducing to their lowest factors

10! = (2×5)×(3×3)×(2×2×2) × 7!

Rearranging the factors, we have;

10! = (2×3)×(5)×(2×2)×(3)×2 × 7!

10! = 6×5×4×3×2 ×7!

10! = 6! 7! (Verified)

b) 10!=7!5!3!

10! = 10×9×8×7!

10! = (2×5)×(3×3)×(2×2×2) × 7!

Rearranging the factors, we have;

10! = (2×3)×(5)×(2×2)×(3)×2× 7!

10! = (3×2×1) × (5×4×3×2×1) × 7!

10! = 3! × 5! × 7! = 7!5!3! (Verified)

c) 16!= 14!5!2!

16! = 16×15×14!

16! = (2×2×2×2) × (5×3) × 14!

Rearranging the factors.

16! = (2) × (5) × (2×2) × (3) × (2) ×14!

16! = (2!) ×(5×4×3×2) × 14!

16! = 2! × 5! × 14!

16! = 14!5!2! (Verified)

d) 9!=7!3!3!2

9! = 9×8×7!

9! = (3×3) × (2×2×2) × 7!

Rearranging the factors

9! = (3×2) ×(3×2) ×(2) × 7!

9! = 3! × 3! ×2! × 7!

9! = 7!3!3!2! (Verified)

3 0
3 years ago
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