For a logarithmic function, we have a restriction on the domain.
Since log(0) isn't defined, we say that there is an asymptote at x = 0.
Thus, for the regular logarithmic function y = log(x), x > 0.
We can then say (x + 4) > 0, since that's when the function of a logarithm is defined as.
x + 4 > 0
x > -4
Thus, the domain of the logarithmic function is x > -4, where x is a real integer.
Answer: B. 2/3; 1
Use the slope-intercept form y = m x + b to find the slope m and y-intercept b
.
Slope:
(2)
/(3)
y-intercept:
(
0
, 1
)
Step-by-step explanation:
Find the slope and y-intercept of the equation. y = (2)/(3)x + 1
Find the Slope and y-intercept
<span>x^2+6x+11=0
After solving this u will bet
X=-6+,-</span>√-8/2
So roots of a equation are imaginary
The product below is equivalent when x > 0 is <u>1/9</u>
<h3>Resolution - Explanation</h3>
Square root is a real number x multiplied by itself - which results in a perfect value, where it is possible to calculate the real proof (which is the square root).
Given the expression,
, first step: we will calculate the root of the numerator and denominator of this fraction:
<u />
<u />


Step two: rearranging the expression and canceling the common factors x, we will have,:


Therefore, the final answer to this multiplication will be 1/9.