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kolezko [41]
3 years ago
6

I don't know this questions so pls help

Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer:

The distance between the two points is 6.3 units

Step-by-step explanation:

Here, we want to find the distance between the two points

We have the equation to find this as follows;

D = √((x2-x1)^2 + (y2-y1)^2

where (x1,y1) = (-4,2) and (x2,y2) = ((2,4)

so we have the length calculated as follows;

D = √(2-(-4))^2 + (4-2)^2

D = √6^2 + 2^2

D = √36 + 4

D = √40

D = 6.3 units

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Which is NOT a true statement?
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option 4

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|a| represents Absolute value, it is the distance from zero that a number is on the number line. And we know distance cannot be negative.

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3 years ago
Henry and reiko both used 1 yard of ribbon to make bows. write two different fractions to show that Henry and reiko use the same
Natalka [10]
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4 0
3 years ago
You are given g(x)=4x^2 + 2x and
Strike441 [17]

Answer:

324

Step-by-step explanation:

Given:

g(x)=4x^2+2x\\ \\f(x)=\int\limits^x_0 {g(t)} \, dt

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f(6)

First, find f(x):

f(x)\\ \\=\int\limits^x_0 {g(t)} \, dt\\ \\=\int\limits^x_0 {(4t^2+2t)} \, dt\\ \\=\left(4\cdot \dfrac{t^3}{3}+2\cdot \dfrac{t^2}{2}\right)\big|\limits^x_0\\ \\=\left(\dfrac{4t^3}{3}+t^2\right)\big|\limits^x_0\\ \\= \left(\dfrac{4x^3}{3}+x^2\right)-\left(\dfrac{4\cdot 0^3}{3}+0^2\right)\\ \\=\dfrac{4x^3}{3}+x^2

Now,

f(6)\\ \\=\dfrac{4\cdot 6^3}{3}+6^2\\ \\=288+36\\ \\=324

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3 years ago
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