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kompoz [17]
3 years ago
8

A model rocket is 3 inches long. the real rocket is 120 ft long. what is the unit rate that describes the relationship of the re

al rocket to the model rocket?
A. 360 ft/in
B. 360 in/ft
C. 40 ft/in
D. 40 in/ft
Mathematics
2 answers:
V125BC [204]3 years ago
6 0

Answer: Option C

40 ft/in

Step-by-step explanation:

We know that:

model rocket = 3 inches long

real rocket = 120 ft long

To find the unit rate that describes the relationship of the real rocket to the model rocket, you must divide the length of the real rocket by the length of the model rocket:

r =\frac{120\ ft}{3\ in}

r =40\frac{ft}{in}

This means that every inch in length of the model rocket equals 40 feet of real rocket length

The answer is the option C

lora16 [44]3 years ago
4 0

Answer:

40 ft/in

Step-by-step explanation:

There is 40 feet for every inch of the model

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Step-by-step explanation:

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A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
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