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motikmotik
3 years ago
6

Mr.gilliam is 3 years younger than his wife.the sum of their ages is 95.how old is mr.gilliam

Mathematics
2 answers:
Maurinko [17]3 years ago
5 0
C= a+b
b= a-3


95= a+a-3
95=2a-3
98=2a
a= 49


b=49-3
b=46


This is a system of equations. The ages are 49 and 46. Mr. Gilliam is 46. Their ages are equal to 95 so I put two variables equal to 95. And one of the ages is 3 years younger than the other so I did another equation subtracting 3 from a variable. Then I plugged in the numbers! Check it out and ask me if you have questions! :)
Usimov [2.4K]3 years ago
3 0
X = the age of Mr. Gilliam
His wife is 3 years older, so the age of Mr. Gilliam's wife = x+3
The sum of their ages is 95.

x+x+3=95 \\
2x+3=95 \\
2x=95-3 \\
2x=92 \\
x=46

Mr. Gilliam is 46 years old.
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Sphinxa [80]

Answer:

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Step-by-step explanation:

<u>Given :- </u>

  • A geometric sequence is given to us which is 9 , -18 , 36.

And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .

<u>Common Ratio :- </u>

:\implies CR = -18÷ 9 = -2

<u>The </u><u>9</u><u> th term :- </u>

:\implies T_n = arⁿ - ¹

:\implies T_9 = 9× (-2) ⁹ - ¹

:\implies T_9 = 9 × (-2)⁸

:\implies T_9 = 9 × 256

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3 0
3 years ago
4. a) A ping pong ball has a 75% rebound ratio. When you drop it from a height of k feet, it bounces and bounces endlessly. If t
Klio2033 [76]

First part of question:

Find the general term that represents the situation in terms of k.

The general term for geometric series is:

a_{n}=a_{1}r^{n-1}

a_{1} = the first term of the series

r = the geometric ratio

a_{1} would represent the height at which the ball is first dropped. Therefore:

a_{1} = k

We also know that the ball has a rebound ratio of 75%, meaning that the ball only bounces 75% of its original height every time it bounces. This appears to be our geometric ratio. Therefore:

r=\frac{3}{4}

Our general term would be:

a_{n}=a_{1}r^{n-1}

a_{n}=k(\frac{3}{4}) ^{n-1}

Second part of question:

If the ball dropped from a height of 235ft, determine the highest height achieved by the ball after six bounces.

k represents the initial height:

k = 235\ ft

n represents the number of times the ball bounces:

n = 6

Plugging this back into our general term of the geometric series:

a_{n}=k(\frac{3}{4}) ^{n-1}

a_{n}=235(\frac{3}{4}) ^{6-1}

a_{n}=235(\frac{3}{4}) ^{5}

a_{n}=55.8\ ft

a_{n} represents the highest height of the ball after 6 bounces.

Third part of question:

If the ball dropped from a height of 235ft, find the total distance traveled by the ball when it strikes the ground for the 12th time. ​

This would be easier to solve if we have a general term for the <em>sum </em>of a geometric series, which is:

S_{n}=\frac{a_{1}(1-r^{n})}{1-r}

We already know these variables:

a_{1}= k = 235\ ft

r=\frac{3}{4}

n = 12

Therefore:

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{1-\frac{3}{4} }

S_{n}=\frac{(235)(1-\frac{3}{4} ^{12})}{\frac{1}{4} }

S_{n}=(4)(235)(1-\frac{3}{4} ^{12})

S_{n}=910.22\ ft

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