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KIM [24]
2 years ago
12

F(x) = 2/x^2 - 2x - 3 PLS HELP!!!

Mathematics
1 answer:
Marina CMI [18]2 years ago
6 0

Answer: The factored expression is:

2/ (x+1)(x-3)

The domain is (-1,3)

range is y= -1/2

X = 0     Y = (0,-2/3)

HORIZ: Y=0

VERTIC :  x= -1 x=3

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valina [46]

Answer: C

Step-by-step explanation:

3 0
3 years ago
Solve 15(5x−5)+3x=−9(13x+4) . Check your solution.
Iteru [2.4K]
<h2>Answer: 1/5 or 0.2 _____________________________________</h2><h3> Isolate the variable by dividing each side by factors that don't contain the variable. Exact Form: x = 1/5 Decimal Form: x = 0.2</h3><h3>______________________________________________</h3>

Hope this helps!

Also can I please have Brainliest...? 

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8 0
2 years ago
Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probab
Sphinxa [80]

Answer:  a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

Step-by-step explanation:

Problem 8-4 A computer time-sharing system receives teleport inquiries at an average rate of .1 per millisecond. Find the probabilities that the number of inquiries in a particular 50-millisecond stretch will be:

Since we have given that

\lambda=0.1\ per\ millisecond=5\ per\ 50\ millisecond=5

Using the poisson process, we get that

(a) less than or equal to 12

probability=  P(X\leq 12)=\sum _{k=0}^{12}\dfrac{e^{-5}(-5)^k}{k!}=0.9980

(b) equal to 13

probability= P(X=13)=\dfrac{e^{-5}(-5)^{13}}{13!}=0.0013

(c) greater than 12

probability= P(X>12)=\sum _{k=13}^{50}\dfrac{e^{-5}.(-5)^k}{k!}=0.0020

(d) equal to 20

probability= P(X=20)=\dfrac{e^{-5}(-5)^{20}}{20!}=0.00000026

(e) between 10 and 15, inclusively

probability=P(10\leq X\leq 15)=\sum _{k=10}^{15}\dfrac{e^{-5}(-5)^k}{k!}=0.0318

Hence, a) 0.9980, b) 0.0013, c) 0.0020, d) 0.00000026, e) 0.0318

6 0
3 years ago
What is the range of this function?
Snezhnost [94]
Idk idk idk idk idk idk idk
6 0
2 years ago
The rate of change in sales S is inversely proportional to time t (t &gt; 1), measured in weeks. Find S as a function of t when
Zanzabum

Answer:

<h2>S = 250/t</h2>

Step-by-step explanation:

If the rate of change of sales is inversely proportional to the time t, this is expressed mathematically as ΔS ∝ 1/Δt

ΔS = k/Δt where k is the constant of proportionality

If ΔS = S₂-S₁ and Δt = t₂-t₁

S₂-S₁ = k/ t₂-t₁

If the sales after 2 and 4 weeks are 162 units and 287 units respectively, then when S₁  = 162, t₁ = 2 and when   S₂ = 287, t₂ = 4.

On substituting this values into the given functions, we will have;

287 - 162 = k/4-2

125 = k/2

cross multiplying

k = 125* 2

k = 250

Substituting k = 250 into the function ΔS = k/Δt

ΔS = 250/Δt

S = 250/t

<em>Hence the value of S as function of t when the sales after 2 and 4 weeks are 162 units and 287 units, respectively is expressed as S = 250/t</em>

3 0
3 years ago
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