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3 years ago

If p is true and q is false, then p ∧ ~q is true.

Mathematics

1 answer:

Nadusha1986 [10]3 years ago

5 0

Answer:

True

Step-by-step explanation:

true ∧ (not false) . . . . . . . has a truth value of True

_____

The "and" operator gives true if all of its operands are true.

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Giant tortoises move very slowly. They can travel a distance of about 0.17 mile in 1hour. If it travels at the same speed, how f

ELEN [110]

0.17 in 1 hour
0.34 in 2 hours
0.51 in 3 hours
0.68 in 4 hours

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2 years ago

X – y = 3 (line a)

tester [92]

Answer. You must first put the equation into slope-intercept form (y = mx + b). To do this, subtract x from both sides to isolate y. Then, since y will be negative, divide each side by -1, resulting in y = x - 3.

3 0

2 years ago

The high school took two field trips to the Newport Aquarium many many years ago. They used school buses and vans to transport a

il63 [147K]

Answer:

bus = 43

van 12

Step-by-step explanation:

This can be solved using simultaneous equations

Let v represent the number of students that a van carries

Let b represent the number of students that a bus carries

the following equations can be derived from the question

3v + 2b = 122 eqn 1

5v + 3b = 189 eqn 2

Multiply eqn 1 by 5 and eqn 2 by 3

15v + 10b = 610 eqn 3

15v + 9b = 567 eqn 4

Subtract equation 4 from 3

b = 43

Substitute for b in equation 1

3v + 2(43) = 122

solve for v

v = 12

5 0

2 years ago

∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len

leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

AB

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07$

BC

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06$

AC

$d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04$

4 0

2 years ago

What is the standard form equation of the line shown below? Graph of a line going through negative 2, 3 and 1, negative 3

V125BC [204]

Answer:

3. 2x + y = −1

Step-by-step explanation:

To find the equation of the line, we write it first in the slope-intercept form:

$y=mx+q$

where

m is the slope

q is the y-intercept

From the graph, we see that the line crosses the y-axis at y = -1, so the y-intercept is -1:

$q=-1$

Now we have to find the slope, by calculating the rate of change of the line through 2 points:

$m=\frac{y_2-y_1}{x_2-x_1}$

Taking the two points at (-2,3) and (1,-3), we find:

$m=\frac{-3-3}{1-(-2)}=\frac{-6}{3}=-2$

So the equation of the line is

$y=-2x-1$

Now we have to re-arrange it in the standard form, so in the form

$ax+bx=c$

where a, b and c are integer numbers.

To do that, we simply add +2x on both sides of the equation of the line in the slope-intercept form, and we get:

$y+2x=-1$

So, option 3).

6 0

2 years ago