Answer:
BC= 15
if I am right please mark it as brianliest
RemarkIf you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)
Step OneDivide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
y = 6x^(1/2) + 3x^2 Now differentiate that. It should be much easier.
Step TwoDifferentiate the y in the last step.
y' = 6(1/2) x^(- 1/2) + 3*2 x^(2 - 1)
y' = 3x^(-1/2) + 6x I wonder if there's anything else you can do to this. If there is, I don't see it.
I suppose this is possible.
y' = 3/x^(1/2) + 6x
y' =

Frankly I like the first answer better, but you have a choice of both.
Answer:7.967
Step-by-step explanation:
Answer: a.This is the average number of days the house stayed on the market before being sold for $150,000.
Step-by-step explanation:
Given: f(p) be the average number of days a house stays on the market before being sold for price p in $1,000s.
To find the meaning f(150),
here p= 150 which means f(150) is the average number of days a house stays on the market before being sold for price 150 in $1,000s.
And 150 in $ 1,000= $150,000
Therefore, f(150) is the average number of days a house stays on the market before being sold for price $150,000.