Answer:
82.5
Step-by-step explanation:
Step 1: We make the assumption that 200 is 100 % since it is our output value.
Step 2: We next represent the value we seek with x.
Step 3: From step 1, it follows that 100 % = 200.
Step 4: In the same vein, x % = 165 .
Step 5: This gives us a pair of simple equations:
100 % = 200(1).
x % = 165(2).
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
100 % / x % = 200/165
Step 7: Taking the inverse (or reciprocal) of both sides yields
x/100 = 165/200
x = 82.5 %
We can use the Pythagorean Theorem (a^2+b^2=c^2) to find the side lengths.
15^2=12^2+x^2
225=144+x
81=x
Which gives us that x=9 (you have to remember to find the square root)
Perimeter is 2l+2w, so 2(12)+2(9) = 42
Perimeter = 42
As for the area, we just multiply 9 by 12 to get us 108
Area = 108
:)
Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
Volume of a cylinder = pi r^2 h where r = radius of the base and h = the height.
so if we are given a radius of 2 cm and a volume of 180 cm^3 we work out the height as follows:-
180 = pi * 2^2 * h
h = 180 / (pi*2^2)
height h = 180 / 4pi = 14.32 cm to nearest hundredth
Answer:
They are compatible
Step-by-step explanation:
The first thing is to say that an "ace" and that it is a "coarse"
"ace" is card number 1. Group A
"coarse" is a type of the deck, found from number 1 to card 13. Group B
Thus:
Calculate A U B:
1 to 13 + 1 of the other types of cards in the deck.
At intersection B:
1 of "coarse"
Therefore, if group A is compatible with group B