Answer:
x≥5
Step-by-step explanation:
The function f(x)=2*sqrt(x-5) is transformed from the parent function f(x)=sqrt(x) by:
vertically stretched by a factor of 2
right 5 units
a parent rational equation has a domain of [0,+∞)
this certain equation is moved 5 units to the right, so the domain is:
[0+5,+∞)⇒[5,+∞)
So the domain of f(x)=2*sqrt(x-5) is [5,+∞)
which as an inequality is x≥5
