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3 years ago

SOMEONE HELP ME PLEASE

Physics

2 answers:

konstantin123 [22]3 years ago

7 0

Solids almost every single time

Allisa [31]3 years ago

6 0

D liquids, hope it helps and sorry if its not correct!

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HELP PLS! :/

deff fn [24]

Answer:

31.28m/s

Explanation:

We can use the third key equation of accelerated motion

Δd = viΔt+1/2aΔt^2

subtitute in the values we know

41.6 = vi(1.89)+1/2(-9.8)(1.89)^2

41.6 = vi(1.89) - 17.52

59.12 = vi(1.89)

vi = 31.28

4 0

3 years ago

By what percent does the braking distance of a car decrease, when the speed of the car is reduced by 10.3 percent? Braking dista

likoan [24]

The braking distance is the distance traveled by a car experiencing a braking force until it comes to rest.

Our initial energy is solely kinetic:
$E_i = \frac{1}{2}mv^2$

And, since the car goes to rest, it is no longer in motion. It will have no kinetic energy.
$E_f = 0$

Therefore, there was work done by the braking force.

$W_B = E_f - E_i = -\frac{1}{2}mv^2$

Recall the definition of work:
$W = F\cdot \Delta x$

Or in this case, since the displacement and breaking force are antiparallel:
$W = -F_B\Delta x$

This is equivalent to the dissipation of kinetic energy:
$W = -F_B\Delta x = -\frac{1}{2}mv^2$

Now, to visualize this, let's rearrange the equation to solve for displacement.

$\Delta x =\frac{mv^2}{2F_B}$

There is a direct, SQUARE relationship between necessary braking distance speed.

If the speed was reduced by 10.3 percent, its new speed is only 89.7% percent of the original, so:
$\Delta x' =\frac{m(0.897v)^2}{2F_B}$

$\Delta x' = 0.8046\Delta x$

The reduction by a percentage is:
$1 - 0.8046 = 0.1954 \\\\\boxed{= 19.54\%}$

6 0

2 years ago

What are nasa's four great observatories and in what parts of the electromagnetic spectrum do they observe?

Hoochie [10]

1) Hubble Space Telescope- Visible and near-ultraviolet
2) Compton Gamma Ray Observatory- Gamma Rays
3) Chandra X-ray Observatory- X-rays
4) Spitzer Space Telescope- infrared

6 0

3 years ago

Read 2 more answers

Match up the following set of words with their definitions.

shepuryov [24]

Answer:

weight
mass
force
magnitude
vector
net force

7 0

3 years ago

an electric device is plugged into a 110v wall socket. if the device consumes 500 w of power, what is the resistance of the devi

andreev551 [17]

Answer: R=24.2Ω

Explanation: Power is rate of work being done in an electric circuit. It relates to voltage, current and resistance through the following formulas:

P=V.i

P=R.i²

$P=\frac{V^{2}}{R}$

The resistance of the system is:

$P=\frac{V^{2}}{R}$

$R=\frac{V^{2}}{P}$

$R=\frac{110^{2}}{500}$

R = 24.2Ω

For the device, resistance is 24.2Ω.

4 0

3 years ago