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maria [59]
4 years ago
12

Rays of light incident on a lens and parallel to the principal axis of the lens converge

Physics
2 answers:
kirill115 [55]4 years ago
8 0
<span>D. in back of the lens, because the rays are unaffected until it goes through the lens. In that moment the direction of the rays is modified, making them get closer to each other and all of them converge in a point behind the lens.</span>
N76 [4]4 years ago
3 0
Focal    point of the lens
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The speed limit on some interstate highways is roughly 80 km/h. What is this in meters per second? How many miles per hour is th
sergey [27]

Answer:

1) Speed in m/s equals 22.22 m/s.

2) Speed in miles per hour equals 49.712 mph.

Explanation:

Since we know that in 1 kilometer there are 1000 meters and in 1 hour there are 3600 seconds hence we can write

80km/h=\frac{80\times 1000m}{3600s}=22.22m/s

Now we know that 1 mile equals 1.609 kilometer  hence we conclude that 1 kilometer equals \frac{1}{1.609}=0.6214mile

Hence

80km/h=\frac{80\times 0.6214miles}{1h}=49.712mph

3 0
4 years ago
An object example to decrease pressure.
Olin [163]

Answer:

To reduce pressure - decrease the force or increase the area the force acts on. If you were standing on a frozen lake and the ice started to crack you could lie down to increase the area in contact with the ice. The same force (your weight) would apply, spread over a larger area, so the pressure would reduce.

3 0
4 years ago
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A piano of mass 852 kg is lifted to a height of 3.5 m. How much gravitational potential energy is added to the piano? Accelerati
JulsSmile [24]
m=852 \ kg \\ h=3,5 \ m \\ g=9,8 \ m/s^2 \\ \boxed{P_e-?} \\ \bold{Solving:} \\ \boxed{P_e=m \cdot g \cdot h} \\ P_e=852 \ kg \cdot 9,8 \ m/s^2 \cdot 3,5 \ m =8 \ 349,6 \ N \cdot 3,5 \ m \\ \Rightarrow \boxed{P_e=29 \ 223,6 \ J}
7 0
3 years ago
A cart starting from rest rolls down a frictionless 1.0 m high hill. It travels a distance 2.0 m along the rough bottom surface
Rzqust [24]

Answer:

Option B is correct.

Explanation:

Given data

Height of the hill = AB = 1 m

Distance traveled  along the rough bottom surface = AC = 2 m

Now from the ΔABC

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\sin \theta = \frac{1}{2}

\theta = 30 °

We know that  the coefficient of kinetic friction is

\mu = \tan \theta

\mu = \tan 30

\mu = 0.5

This is the value of the coefficient of kinetic friction

Thus option B is correct.

8 0
3 years ago
What factor contributes the most to the warm climate of Kaula Lumpur?
inna [77]

Answer:

Latitude

Explanation:

8 0
3 years ago
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