Answer:
<h2>She gave her brother 6 tickets</h2>
Step-by-step explanation:
This problem is on fractional numbers.
given that she has 60 tickets
1.She used 3/4 of her tickets to play game
=(3/4)*60
=180/4
=45
She is left with (60-45)= 15 tickets
2. She used 1/5 of her remaining tickets for rides
=(1/5)*15
=15/5
=3
She is left with (15-3)= 12 tickets
3. She gave half of her tickets to her brother.
= (1/2)*12
=12/2
= 6
She gave her brother 6 tickets
Answer:
1716 ways
Step-by-step explanation:
Given that :
Number of entrants = 13
The number of ways of attaining first, second and third position :
The number of ways of attaining first ; only 1 person can be first ;
Using permutation :
nPr = n! ÷(n-r)!
13P1 = 13! ÷ 12! = 13
Second position :
We have 12 entrants left :
nPr = n! ÷(n-r)!
12P1 = 12! ÷ 11! = 12
Third position :
We have 11 entrants left :
nPr = n! ÷(n-r)!
11P1 = 11! ÷ 10! = 11
Hence, Number of ways = (13 * 12 * 11) = 1716 ways
Answer: 25%
100/56 = 1.785714285714286
1.785714285714286 x 14 = 25
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.
2. So f(x)=
3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:
4. Now, f(0)=-5 so
5. the function is
where a can be any real number except 0
