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AleksAgata [21]
2 years ago
6

1. The area of a circle is 60 square units. What is the area of ...

Mathematics
1 answer:
AVprozaik [17]2 years ago
3 0

Multiply the area of the circle by the percentage:

60 square units x 50% = 60 x 0.50 = 30

50% 0f the circle id 30 square units.

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Question 6 Multiple Choice Worth 1 points)
OleMash [197]

Answer:

Quantity A because it changes with gravitational pull.

Explanation:

Mass defines the constitutive matter of an object. It is immutable (does not change). Although it could be converted into energy, the matter is constant.

On the other hand, the weight of an object (gravitational force) depends on the acceleration due to gravity.

That is why an astronaut weighs about three times more on earth than on Mars. The gravitational acceleration on Mars is about one third that on earth.

5 0
2 years ago
Green yellow purple or grey pins in a bag.
DiKsa [7]

Answer:

yellow

Step-by-step explanation:

I choose yellow because it's a beautiful spring color

3 0
2 years ago
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What is the answer to this problem 75=3(-6n-5)
devlian [24]

Answer:

n=-5

Step-by-step explanation:

first you have to distribute the 3 to the -6 and the 5. In return u will get -18n and 15. then you have to cancel like terms. then you have to add 18 to the 75 which gives you 93. then you divide -18 by 93 which gives you -5.166 repeating... so all you have to do is round. your final answer will be -5.

5 0
3 years ago
NEED HELP ASAP ALGEBRA 2​
ki77a [65]

Answer:

15

Step-by-step explanation:

Use the pythagorean theorem.

A² + B² = C²

In this case, A = 8, B is unknown, and C = 17. B is the side that we want to calculate.

8² + B² = 17²

64 + B² = 289

B² = 225

B = √225 = 15

7 0
3 years ago
At the beginning of year 1, Bode invests $250 at an annual simple interest rate of 3%. He makes no deposits to or withdrawals fr
Dennis_Churaev [7]
The initial investment = $250
<span>annual simple interest rate of 3% = 0.03
</span>
Let the number of years = n
the annual increase = 0.03 * 250
At the beginning of year 1 ⇒ n = 1 ⇒⇒⇒ A(1) = 250 + 0 * 250 * 0.03 = 250

At the beginning of year 2 ⇒ n = 2 ⇒⇒⇒ A(2) = 250 + 1 * 250 * 0.03
At the beginning of year 3 ⇒ n = 3 ⇒⇒⇒ A(2) = 250 + 2 * 250 * 0.03
and so on .......
∴ <span>The formula that can be used to find the account’s balance at the beginning of year n is:
</span>
A(n) = 250 + (n-1)(0.03 • 250)
<span>At the beginning of year 14 ⇒ n = 14 ⇒ substitute with n at A(n)</span>
∴ A(14) = 250 + (14-1)(0.03*250) = 347.5

So, the correct option is <span>D.A(n) = 250 + (n – 1)(0.03 • 250); $347.50 </span>
4 0
3 years ago
Read 2 more answers
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