Using the Fundamental Counting Theorem, it is found that there are 10 positive three-digit integers have the hundreds digit equal to 7 and the units (ones) digit equal to 1.
<h3>What is the Fundamental Counting Theorem?</h3>
It is a theorem that states that if there are n things, each with 
ways to be done, each thing independent of the other, the number of ways they can be done is:
The number of options for each selection are given as follows, considering there are 10 possible digits, and that the last two are fixed at 7 and 1, respectively:
Hence, the number of integers is given by:
N = 10 x 1 x 1 = 10.
More can be learned about the Fundamental Counting Theorem at brainly.com/question/24314866
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Answer:
If I'm not mistaking, they want you to find the number in the middle that's between X and Z.
That number would be 3.
Hope this helps a bit! :)
Answer: see proof below
<u>Step-by-step explanation:</u>
Statement Reason
1. YO = NZ 1. Given
2. OZ = OZ 2. Reflexive Property
3. YO + OZ = YZ 3. Segment Addition Property
NZ + OZ = NO
4. YO + OZ = NZ + OZ 4. Addition Property
5. YZ = NO 5. Substitution
6. ∠M ≅ ∠X 6. Given
7. ∠N ≅ ∠Y 7. Given
8. ΔMNO ≅ ΔXYZ 8. AAS Congruency Theorem
Answer:
0-3=X
Step-by-step explanation:
you start off with zero, and go back 3. which equals 3- so it makes X, -3
Answer:Y=30x
Step-by-step explanation:
90-0=90
9-6=3
90/3=30
y=30x
