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Vilka [71]
3 years ago
6

PLEASE HELP ASAP!!!!

Mathematics
1 answer:
lina2011 [118]3 years ago
8 0
<h3>Answer:</h3>

System

  • p + m = 10
  • 0.8m = 0.4·10

Solution

  • p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>Step-by-step explanation:</h3>

(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.

For the total amount of mix:

... p + m = 10

For the quantity of peanuts in the mix:

... p + 0.2m = 0.6·10

For the quantity of almonds in the mix:

... 0.8m = 0.4·10

For the ratio of peanuts to almonds:

... (p +0.2m)/(0.8m) = 0.60/0.40

Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.

So, your system of equations could be ...

  • p + m = 10
  • 0.8m = 0.4·10

___

(b) Dividing the second equation by 0.8 gives

... m = 5

Using the first equation to find p, we have ...

... p + 5 = 10

... p = 5

5 lb of peanuts and 5 lb of mixture are required.

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9) If m/1 = 45° and 21 and 22 are complementary angles. Find m22.​
Allisa [31]

❄ Hi there,

keeping in mind that the sum of complementary angles is 90°,

set up an equation, letting \angle2  be x  –

\triangleright \ \sf{\angle1+x=90}                 {and we know that \boxed{\angle1=45}}

\triangleright \ \sf{45+x=90}

\triangleright \ \sf{x=90-45}

\triangleright \ \sf{x=45}

\triangleright \ \sf{\angle2=45\textdegree}

      __________

Keeping in mind that a right angle is 90°,

set up an equation, letting \angle1 be x:

\triangleright \ \sf{x+\angle2=90}                       {and we know that \boxed{\angle2=63}}

\triangleright \ \sf{x+63=90}

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❄

5 0
2 years ago
Would the hypotenuse of a right triangle with a vertical length of 6 and a horizontal length of 10 have the same slope as the hy
Elodia [21]
No

1. Vertical 6, horizontal 10
6/10 = 3/5 slope

2. (Red) vertical -2, horizontal 3
-2/3 does not equal 3/5

3. (Blue) vertical 4, horizontal 6
4/6 = 2/3 but does not equal 3/5
3 0
3 years ago
Ebi, Jose, Derell, and Asami measured their heights. Ebi's height was 2.5 cm greater than Jose's height. Jose's height was 3.1 c
irga5000 [103]
Start with assigning each person with a variable to represent their height

Ebi: e
Jose: j
Derell: d
Asami: a

Ebi'd height was 2.5 cm greater than Jose's height

j + 2.5 = e

Jose's height was 3.1 cm greater than Derell's

d + 3.1 = j

Derell's height is 0.4 cm less than Asami's height

a - 0.4 = d

Ebi is 162.5 cm tall

e = 162.5

So, plug in 162.5 into any of the above equations were there is a variable of e

j + 2.5 = e

j + 2.5 = 162.5

Subtract 2.5 from both sides of the equation

j = 160 cm

Jose's height is 160 cm

Now, plug in 160 into any of the above equations where there is a j

d + 3.1 = j

d + 3.1 = 160

Subtract 3.1 from both sides of the equation 

d = 156.9 cm

Derell's height 156.9 cm

so, plug in 156.9 into any of the above equations where there is a d

a - 0.4 = d

a - 0.4 = 156.9

Add 0.4 on both sides of the equation

a = 157.3 cm

Asami's height is 157.3 cm



7 0
3 years ago
Read 2 more answers
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Dafna11 [192]

Answer:

I dont understand th equestion

Step-by-step explanation:

4 0
3 years ago
Please give me the answer i cant get it
dexar [7]

Answer:

i believe its c

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
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