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2 years ago

45 5/6% as a fraction in its simplest form Please hurry need in 5 minutes!!!!!?!?!?!

Mathematics

1 answer:

Leya [2.2K]2 years ago

8 0

Answer:

45 5/6 = 275/6 which is the simplest form

Step-by-step explanation:

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Part of the graph of the function f(x) = (x - 1)(x + 7) is

algol [13]

Answer:

True: B, C and D

Step-by-step explanation:

The graph of the function is shown in the attached diagram.

The vertex of the parabola (parabola is the graph of the function f(x)) is at (-3,-16), because

$x_v=\dfrac{1+(-7)}{2}=-3\\ \\y_v=f(-3)=(-3-1)(-3+7)=-4\cdot 4=-16$

So, option A is false and option B is true.

As you can see from the graph, the function is increasing for all x>-3, thus option C is true.

The graph is positive for x<-7 and x>1 and negative for -7<x<1, so option D is true and option E is false.

8 0

3 years ago

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JNZ~ KOA. Find the unknown measures

shepuryov [24]

Answer:

Step-by-step explanation:

If ΔJNZ and ΔKOA are similar, then corresponding sides are in proportion and corresponding angles are congruent.

We have the proportion:

$\dfrac{JN}{KO}=\dfrac{NZ}{OA}=\dfrac{ZJ}{AK}$

and equations:

$m\angle N=m\angle O=90^o\\m\angle Z=m\angle A=28^o\\m\angle J=m\angle K=62^o$

We have:

$JN=8\ in,\ NZ=15\ in,\ KO=4\ in,\ AK=x\ in,\ ZJ=y\ in$

For y we must use the Pythagorean theorem:

$ZJ^2=JN^2+NZ^2\\\\y^2=8^2+15^2\\\\y^2=64+225\\\\y^2=289\to y=\sqrt{289}\\\\y=17\ in$

$\dfrac{JN}{KO}=\dfrac{ZJ}{AK}\to\dfrac{8}{4}=\dfrac{17}{x}$ <em>cross multiply</em>

$8x=(4)(17)$

$8x=68$ <em>divide both sides by 8</em>

$x=8.5\ in$

4 0

3 years ago

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F(x) = -3(x-1) find f(o).

navik [9.2K]

Answer:

f(0) = 3

Step-by-step explanation:

Step 1: Distribute

f(x) = -3x + 3

Step 2: Plug in

f(0) = -3(0) + 3

f(0) = 3

5 0

3 years ago

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Write the equation in standard form for the circle that has a diameter with endpoints (22,0) and (2,0)

vovikov84 [41]

Answer:

(x - 12)² + y² = 100

Step-by-step explanation:

The standard form of the equation of a circle is;

(x - a)² + (y - b)² = r²

where:

a and b are the coordinates of the centre of the circle

r is the radius

We are given the coordinates of the endpoints of the diameter as; (22,0) and (2,0)

Thus, the centre of the circle would be at the mid point of the endpoints of the diameter.

Coordinates of the centre is;

((22 + 2)/2), (0 +0)/2))

This is;

(12, 0)

So, a = 12 and b = 0

Now,to get the radius r, we will use the formula;

r = √[(x2 - x1)² + (y2 - y1)²]

Where;

(x1, y1) and (x2, y2) are 2 points namely (12,0) and (22, 0)

r = √[(12 - 22)² + (0 - 0)²]

r = √(-10)²

r = √100

r = 10

Thus,equation of the circle is;

(x - 12)² + (y - 0)² = 10²

(x - 12)² + y² = 100

7 0

3 years ago

Find all solutions of the equation in the interval [0, 2 pi) 2 cos0-1=0

ddd [48]

Answer:

θ = π/3, 5π/3

Step-by-step explanation:

2 cos θ - 1 = 0

2 cos θ = 1

cos θ = 1/2

θ = π/3, 5π/3

7 0

3 years ago

Read 2 more answers