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Angelina_Jolie [31]
3 years ago
9

A copy machine can print 480 copies every 4 minutes. A teacher printed 720 copies. How long did it take to print?

Mathematics
2 answers:
Katarina [22]3 years ago
5 0
480/4= 60 per minute
720/60= 12
It took 12 minutes to print
Dafna1 [17]3 years ago
3 0

Answer:

6 minutes

Step-by-step explanation:

every minute is 120

720/120=6

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Can someone plzz help me you got to zoom in !!!
daser333 [38]

1. 140 - The reason it would be one 40 is honestly a really simple explanation. Is the ratio of boys to girls in 7-2 and the amount of girls is 40. That means that per 1 number, is 20 people since 40 divided by 2 is 20. So if I do 2 x 7 that would be 140.

2. I didnt really understand this one sorryyy.

3. 1200 (same rule applies) - Since The ratio is 1:11 and the 1 represents 100 beans. If I doo 100 x 11 that would be 1100, then I would add the 1100 to the 100 (from the 1) and that would be 1200.

4. 6:7 - If I do 650 - 350 that would be 300. Which means the ratio would be 300:350. But once simplified the answer would be 6:7.

5. 1:2 - 720 - 240 is 480. Therefore the ratio would be 240:480. Once simplified, the ratio is 1:2.

Hope this helped. Good luck!!! xo

3 0
3 years ago
Read 2 more answers
Algebra 1: Factoring Polynomials Factor the common factor out of each expression: 40n^4m^2+40n^3m^3-32n^3
Nina [5.8K]
Taking out the greatest common factor

GCF of 40, 40 and 32  = 8
GCF of n^4, n^3 and n^3  is n^3

so the factors are

8n^3(5nm^2 +5m^3 - 4)
7 0
4 years ago
Sketch a cylinder with radius 8 feet and height 3 feet, then find the volume.
4vir4ik [10]

Answer: 339.29ft^3

Step-by-step explanation:

The formula for a cylinder is πr^2h

In your scenario, r=8 and h=3 so put those into the equation -

π8^2(3) and just solve!

7 0
3 years ago
An aeroplane X whose average speed is 50°km/hr leaves kano airport at 7.00am and travels for 2 hours on a bearing 050°. It then
Zigmanuir [339]

Answer:

(a)123 km/hr

(b)39 degrees

Step-by-step explanation:

Plane X with an average speed of 50km/hr travels for 2 hours from P (Kano Airport) to point Q in the diagram.

Distance = Speed X Time

Therefore: PQ =50km/hr X 2 hr =100 km

It moves from Point Q at 9.00 am and arrives at the airstrip A by 11.30am.

Distance, QA=50km/hr X 2.5 hr =125 km

Using alternate angles in the diagram:

\angle Q=110^\circ

(a)First, we calculate the distance traveled, PA by plane Y.

Using Cosine rule

q^2=p^2+a^2-2pa\cos Q\\q^2=100^2+125^2-2(100)(125)\cos 110^\circ\\q^2=34175.50\\q=184.87$ km

SInce aeroplane Y leaves kano airport at 10.00am and arrives at 11.30am

Time taken =1.5 hour

Therefore:

Average Speed of Y

=184.87 \div 1.5\\=123.25$ km/hr\\\approx 123$ km/hr (correct to three significant figures)

(b)Flight Direction of Y

Using Law of Sines

\dfrac{p}{\sin P} =\dfrac{q}{\sin Q}\\\dfrac{125}{\sin P} =\dfrac{184.87}{\sin 110}\\123 \times \sin P=125 \times \sin 110\\\sin P=(125 \times \sin 110) \div 184.87\\P=\arcsin [(125 \times \sin 110) \div 184.87]\\P=39^\circ $ (to the nearest degree)

The direction of flight Y to the nearest degree is 39 degrees.

7 0
3 years ago
Marcia claims that the GCF for 2x^2, 4xy and 8xy^4 is 8x^2y^4. Is she correct? If not, what is the GCF?
posledela
The GCF is what they all have in common.
2x is the only thing they ALL share.
5 0
3 years ago
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