Stop 1 : -
15 + 5 = 20
20 - 2 = 18
So, on the first stop 18 passengers were left on the bus going to the next stop.
Stop 2 : -
18 + 3 = 21
21 - 15 = 6
So, 6 passengers get off at the 2nd stop.
Hope I helped ya!!
Dang...H0: μ = 115
HA: μ ≠ 115
Sample mean = 120
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (120-115) / 2.5
z = 2
p-value = 2 P( z > 2) = 2(0.0228) = 0.0456
the data are statistically significant at level = .05, but not at level = .01.
2)
H0: μ = 115
HA: μ ≠ 115
Sample mean = 119
Standard deviation = 25
Standard error of mean = σ / √ n
Standard error of mean = 25 / √ 100
SE = 25/10
Standard error of mean 2.5
z = (xbar- μ ) / SE
z = (119-115) / 2.5
z = 1.6
p-value = 2P( z > 1.6) = 2(0.0548) =0.1096
3)
a statement about the population the researcher suspects is true, and is trying to find evidence for.
4)
Sample mean = 80
Standard deviation = 20
Standard error of mean = σ / √ n
Standard error of mean = 20 / √ 100
SE = 20/10
The Standard error of mean 2
Confidence interval 80-(2)(1.645)
and 80+(2)(1.645)
(76.7, 83.3)
Higher standard deviation shows a greater spread of the data.
2005 - sd=3.5
2006 - sd=2.8
2007 - sd=1.0
2008 - sd=4.0
The correct statement is the last statement which says the game scores of season 2005 have a greater spread than the game scores of season 2006
Answer:
yes
Step-by-step explanation:
5x6=30
3x6=18
